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1.1.1 如何实现一个高效的单向链表逆序输出？答案有误 #29

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jihongboo opened this issue Aug 6, 2019 · 0 comments
Open

1.1.1 如何实现一个高效的单向链表逆序输出？答案有误 #29

jihongboo opened this issue Aug 6, 2019 · 0 comments

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@jihongboo
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node* pcur=head->next;
此处应修改为 node* pcur=head， 否则输出时将会丢失第一个元素。
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