Difficulty: Easy
https://leetcode.com/problems/path-sum/
The code is shown below:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def hasPathSum(self, root: Optional[TreeNode], targetSum: int) -> bool:
if not root:
return False
def backtracking(node, path_sum):
if not node.left and not node.right:
if path_sum == targetSum:
return True
else:
return False
if node.left:
if backtracking(node.left, path_sum + node.left.val): return True
if node.right:
if backtracking(node.right, path_sum + node.right.val): return True
return False
return backtracking(root, root.val)