Power of a number in c++

#include<bits/stdc++.h>
using namespace std;

int pow(int a,int n)
{
    int res=1;
    while(n)
    {
        if(n%2)
        {
            res=(res*a);
            n--;
        }
        else
        {
            a=a*a;
            n/=2;
        }
        
    }
    return res;
}
int main()
{
    int n,base;
    cin>>n>>base;
    cout<<pow(base,n)<<endl;
    return 0;
}