diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql index 2e89fa7af..08b6fe726 100644 --- a/02_activities/assignments/assignment1.sql +++ b/02_activities/assignments/assignment1.sql @@ -4,21 +4,34 @@ --SELECT /* 1. Write a query that returns everything in the customer table. */ +SELECT* +FROM customer; /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, sorted by customer_last_name, then customer_first_ name. */ +SELECT* +FROM customer +ORDER BY customer_last_name, customer_first_name +LIMIT 10; --WHERE /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */ -- option 1 +SELECT* +,quantity*cost_to_customer_per_qty as price +FROM customer_purchases +WHERE product_id=4 OR product_id=9; -- option 2 - +SELECT* +,quantity*cost_to_customer_per_qty as price +FROM customer_purchases +WHERE product_id IN (4,9); /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), @@ -27,9 +40,32 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either: 2. one condition using BETWEEN */ -- option 1 - +SELECT +product_id, +vendor_id, +market_date, +customer_id, +quantity, +cost_to_customer_per_qty, +transaction_time, +quantity*cost_to_customer_per_qty AS price +FROM customer_purchases + +WHERE vendor_id>=8 AND vendor_id<=10; -- option 2 +SELECT +product_id, +vendor_id, +market_date, +customer_id, +quantity, +cost_to_customer_per_qty, +transaction_time, +quantity*cost_to_customer_per_qty AS price +FROM customer_purchases + +WHERE vendor_id BETWEEN 8 AND 10; @@ -39,17 +75,52 @@ Using the product table, write a query that outputs the product_id and product_n columns and add a column called prod_qty_type_condensed that displays the word “unit” if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ +SELECT product_id, product_name, +CASE + WHEN product_qty_type ='unit' + THEN 'unit' + ELSE 'bulk' +END AS prod_qty_type_condensed +FROM product; /* 2. We want to flag all of the different types of pepper products that are sold at the market. add a column to the previous query called pepper_flag that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ +SELECT product_id, product_name, +CASE + WHEN product_qty_type ='unit' + THEN 'unit' + ELSE 'bulk' +END AS prod_qty_type_condensed + +,CASE + WHEN product_name LIKE '%epper%' + THEN 1 + ELSE 0 +END AS pepper_flag + +FROM product; + --JOIN /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */ +SELECT +vendor_name, +vendor_type, +vendor_owner_first_name, +vendor_owner_last_name, +booth_number, +market_date + +FROM vendor +INNER JOIN vendor_booth_assignments +ON vendor.vendor_id=vendor_booth_assignments.vendor_id + +ORDER BY vendor_name, market_date; @@ -60,6 +131,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t /* 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per vendor_id. */ +SELECT +vendor_id, +COUNT(vendor_id) AS vendor_booth_rent_times +FROM vendor_booth_assignments +GROUP BY vendor_id; /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper @@ -67,6 +143,25 @@ sticker to everyone who has ever spent more than $2000 at the market. Write a qu of customers for them to give stickers to, sorted by last name, then first name. HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ +SELECT +customer_last_name, +customer_first_name, +customer_postal_code, +x.amount_spent /*x indicated condensed customer_purchases based on the amount each customer has ever spent */ + +FROM customer +INNER JOIN( + +SELECT +customer_id, +SUM(quantity*cost_to_customer_per_qty) AS amount_spent + +FROM customer_purchases + +GROUP BY customer_id +HAVING amount_spent > 2000.0) x +ON customer.customer_id=x.customer_id +ORDER BY customer_last_name, customer_first_name; @@ -82,6 +177,24 @@ When inserting the new vendor, you need to appropriately align the columns to be VALUES(col1,col2,col3,col4,col5) */ +-- if a table named new_vendor exists, delete it, other do NOTHING + +DROP TABLE IF EXISTS temp.new_vendor; + + +--make the TABLE +CREATE TABLE temp.new_vendor AS + +-- definition of the TABLE +SELECT * + +FROM vendor; + + +INSERT INTO temp.new_vendor(vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name) +VALUES (10, 'Thomass_Superfood_Store', 'Fresh_Focused_store', 'Thomas', 'Rosenthal'); + + -- Date @@ -89,7 +202,13 @@ VALUES(col1,col2,col3,col4,col5) HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month and year are! */ +SELECT +customer_id, +strftime('%m',market_date) as purchase_month, +strftime('%Y',market_date)as purchase_year +FROM customer_purchases +ORDER BY customer_id /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. @@ -98,3 +217,18 @@ Remember that money spent is quantity*cost_to_customer_per_qty. HINTS: you will need to AGGREGATE, GROUP BY, and filter... but remember, STRFTIME returns a STRING for your WHERE statement!! */ + +SELECT +customer_id, +strftime('%m', market_date) as purchase_month, +strftime('%Y', market_date)as purchase_year, +SUM(quantity*cost_to_customer_per_qty) AS purchase_spending_in_April_2022 + +FROM customer_purchases +WHERE +strftime('%m',market_date) = '04' +AND +strftime('%Y',market_date) = '2022' + +GROUP BY customer_id + diff --git a/02_activities/assignments/assignment1_logical_model.pdf b/02_activities/assignments/assignment1_logical_model.pdf new file mode 100644 index 000000000..0377f6b9a Binary files /dev/null and b/02_activities/assignments/assignment1_logical_model.pdf differ