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Alexatug merged 2 commits into from
Aug 22, 2025
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assignment1 sql #1

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assignment1 sql
Alexatug Aug 10, 2025
8849202
updated the assignment1 according to reviewer comment
Alexatug Aug 13, 2025
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138 changes: 136 additions & 2 deletions 02_activities/assignments/assignment1.sql
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Original file line number Diff line number Diff line change
Expand Up @@ -4,21 +4,34 @@

--SELECT
/* 1. Write a query that returns everything in the customer table. */
SELECT*
FROM customer;



/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */
SELECT*
FROM customer
ORDER BY customer_last_name, customer_first_name
LIMIT 10;



--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1
SELECT*

,quantity*cost_to_customer_per_qty as price
FROM customer_purchases
WHERE product_id=4 OR product_id=9;

-- option 2

SELECT*
,quantity*cost_to_customer_per_qty as price
FROM customer_purchases
WHERE product_id IN (4,9);


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -27,9 +40,32 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
2. one condition using BETWEEN
*/
-- option 1

SELECT
product_id,
vendor_id,
market_date,
customer_id,
quantity,
cost_to_customer_per_qty,
transaction_time,
quantity*cost_to_customer_per_qty AS price
FROM customer_purchases

WHERE vendor_id>=8 AND vendor_id<=10;

-- option 2
SELECT
product_id,
vendor_id,
market_date,
customer_id,
quantity,
cost_to_customer_per_qty,
transaction_time,
quantity*cost_to_customer_per_qty AS price
FROM customer_purchases

WHERE vendor_id BETWEEN 8 AND 10;



Expand All @@ -39,17 +75,52 @@ Using the product table, write a query that outputs the product_id and product_n
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

SELECT product_id, product_name,
CASE
WHEN product_qty_type ='unit'
THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed

FROM product;

/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */

SELECT product_id, product_name,
CASE
WHEN product_qty_type ='unit'
THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed

,CASE
WHEN product_name LIKE '%epper%'
THEN 1
ELSE 0
END AS pepper_flag

FROM product;



--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
SELECT
vendor_name,
vendor_type,
vendor_owner_first_name,
vendor_owner_last_name,
booth_number,
market_date

FROM vendor
INNER JOIN vendor_booth_assignments
ON vendor.vendor_id=vendor_booth_assignments.vendor_id

ORDER BY vendor_name, market_date;



Expand All @@ -60,13 +131,37 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */

SELECT
vendor_id,
COUNT(vendor_id) AS vendor_booth_rent_times
FROM vendor_booth_assignments
GROUP BY vendor_id;


/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
SELECT
customer_last_name,
customer_first_name,
customer_postal_code,
x.amount_spent /*x indicated condensed customer_purchases based on the amount each customer has ever spent */

FROM customer
INNER JOIN(

SELECT
customer_id,
SUM(quantity*cost_to_customer_per_qty) AS amount_spent

FROM customer_purchases

GROUP BY customer_id
HAVING amount_spent > 2000.0) x
ON customer.customer_id=x.customer_id
ORDER BY customer_last_name, customer_first_name;



Expand All @@ -82,14 +177,38 @@ When inserting the new vendor, you need to appropriately align the columns to be
VALUES(col1,col2,col3,col4,col5)
*/

-- if a table named new_vendor exists, delete it, other do NOTHING

DROP TABLE IF EXISTS temp.new_vendor;


--make the TABLE
CREATE TABLE temp.new_vendor AS

-- definition of the TABLE
SELECT *

FROM vendor;


INSERT INTO temp.new_vendor(vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES (10, 'Thomass_Superfood_Store', 'Fresh_Focused_store', 'Thomas', 'Rosenthal');




-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.

HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */
SELECT
customer_id,
strftime('%m',market_date) as purchase_month,
strftime('%Y',market_date)as purchase_year

FROM customer_purchases
ORDER BY customer_id


/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Expand All @@ -98,3 +217,18 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */


SELECT
customer_id,
strftime('%m', market_date) as purchase_month,
strftime('%Y', market_date)as purchase_year,
SUM(quantity*cost_to_customer_per_qty) AS purchase_spending_in_April_2022

FROM customer_purchases
WHERE
strftime('%m',market_date) = '04'
AND
strftime('%Y',market_date) = '2022'

GROUP BY customer_id

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