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+ //This algorithm at the start as parametr takes the number of items, which recursion will execute.
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+ //The variable ${startNum} specifies the first two starting numbers.
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+
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+ const fibonacciMax = ( max ) => {
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+ let startNum = [ 0 , 1 ] ;
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+ for ( let i = startNum [ 1 ] ; i < max ; i ++ ) {
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+ let nextNum = startNum [ i ] + startNum [ i - 1 ] ;
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+ startNum . push ( nextNum ) ;
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+ }
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+ console . log ( startNum . join ( ", " ) ) ;
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+ }
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+
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+ //Enter the number of items as argument.
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+ fibonacciMax ( 10 ) ;
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+ //The following algorithms is to test that your input is number or string...
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+ //If this is number, checks if a number is double by 3, 5 or either way. If string - return string.
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+ //What will happen if your input is nothing?
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+
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+ const funFunction = ( num ) => {
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+ let f = "FIZZ" ;
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+ let b = "BUZZ" ;
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+
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+ for ( let i = 0 ; i < num && ! isNaN ( num ) ; i ++ ) {
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+ if ( num % 15 === 0 ) {
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+ return f + b ; //FIZZBUZZ
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+ } else if ( num % 3 === 0 ) {
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+ return f ; // FIZZ
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+ } else if ( num % 5 === 0 ) {
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+ return b ; // BUZZ
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+ } else {
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+ return `no ${ f } .. no ${ b } ..` // no FIZZ.. no BUZZ..
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+ } ;
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+ } ;
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+
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+ // this part checks num as contents, if nothing - return information
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+ for ( let i = num ; i === undefined ; i ++ ) {
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+ return `enter your number` ;
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+ } ;
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+
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+ for ( let i = num ; isNaN ( i ) ; i ++ ) {
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+ return `this is string, input number...` ;
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+ } ;
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+
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+ } ;
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+
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+ // START CHECKING
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+ let checkItOut = funFunction ( /*ENTER YOUR NUMBER*/ ) ;
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+ console . log ( `${ checkItOut } ` ) ;
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+ //This function will check which character is the most.
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+ const myFun = ( input ) => {
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+ let obj = { } ;
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+
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+ for ( const element of input ) {
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+ obj [ element ] = obj [ element ] + 1 || 1 ;
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+ } ;
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+
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+ const x = Object . entries ( obj ) . map ( e => e . reverse ( ) ) . sort ( ) . reverse ( ) ;
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+
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+ console . log ( `The letter ${ x [ 0 ] [ 1 ] } are the most numerous, there are ${ x [ 0 ] [ 0 ] } of them` ) ;
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+ }
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+
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+ //Enter a string as an argument:
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+ myFun ( `asfgrgsggtssg` ) ;
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+ //The main advantage of this algorithm is that it checks the string to half, which contributes to less memory loss.
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+
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+ const isPalindrome = ( words ) => {
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+ const lng = words . length ;
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+ for ( let i = 0 ; i < lng / 2 ; i ++ ) {
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+ if ( words [ i ] === words [ lng - 1 - i ] ) {
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+ return true ;
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+ } else {
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+ return false ;
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+ }
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+ }
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+ } ;
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+
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+ //Enter argument(e.g. civic, refer, level) or else word.
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+ let yourPalindrome = isPalindrome ( 'RACECAR' ) ;
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+ console . log ( `${ yourPalindrome } ` ) ;
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+ //This alghoritm change all words, which you will pass.
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+ //Take a moment to review this code...
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+ //I used RegExp for the capture what is to be taken into account.
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+
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+ const changeSign = ( words ) => {
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+
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+ const complete = [ ] ;
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+
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+ for ( let i = 1 ; i <= words . split ( " " ) . length ; i ++ ) {
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+ let regex = / [ ^ a - z A - Z \s ] / g;
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+ let items = words . replace ( regex , '' ) . split ( " " ) ;
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+ let changeItems = items [ i - 1 ] . slice ( 0 , 1 ) . toUpperCase ( ) + items [ i - 1 ] . toLowerCase ( ) . slice ( 1 ) ;
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+
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+ complete . push ( changeItems ) ;
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+ }
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+ console . log ( complete . join ( ' ' ) ) ;
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+ }
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+
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+ // enter your sign here:
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+ changeSign ( `▷wElcoME t@o my ALGHOriTm!𝄞` ) ;
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