Subplots?

[piperod]

I would like to create a figure with several graphs. Does GraphPlot support anything like subplot?

[sbromberger]

Not sure what functionality you're looking for, but you might try "combining" the graphs so that they're effectively disconnected components of a larger graph. That is:

julia> g = CompleteGraph(3)
{3, 3} undirected graph

julia> h = PathGraph(4)
{4, 3} undirected graph

julia> j = blkdiag(g,h)
{7, 6} undirected graph

[afternone]

@piperod There is no subplot function in GraphPlot. You can do subplots like this:

using GraphPlot
using Compose
using LightGraphs

g1 = CompleteGraph(10)
g2 = PathGraph(10)
g3 = barabasi_albert(10,3)
g4 = StarGraph(10)

compose(context(),
(context(0, 0, 0.5, 0.5), gplot(g1)),
(context(0.5, 0, 0.5, 0.5), gplot(g2)),
(context(0, 0.5, 0.5, 0.5), gplot(g3)),
(context(0.5, 0.5, 0.5, 0.5), gplot(g4)))

# add titles
compose(context(),
(context(0, 0, 0.5, 0.05), text(0.5,0,"complete graph",hcenter,vtop)),
(context(0, 0.05, 0.5, 0.45), gplot(g1)),
(context(0.5, 0, 0.5, 0.05), text(0.5,0,"path graph",hcenter,vtop)),
(context(0.5, 0.05, 0.5, 0.45), gplot(g2)),
(context(0, 0.5, 0.5, 0.05), text(0.5,0,"scale-free graph",hcenter,vtop)),
(context(0, 0.55, 0.5, 0.45), gplot(g3)),
(context(0.5, 0.5, 0.5, 0.05), text(0.5,0,"star graph",hcenter,vtop)),
(context(0.5, 0.55, 0.5, 0.45), gplot(g4)))

For more information, please refer to Compose.jl

[duodenum96]

Hello,

Reviving this again; Compose does not support plots generated by plot() function. Is there a way to use Graphplot plot with regular plots in a layout?

Thanks!

[hdavid16]

Have you tried @afternone 's solution?

[duodenum96]

Yes, but compose doesn't support regular plots generated by for example

p1 = plot(...)

[hdavid16]

Then I believe the answer to your original question is no. You could save your GraphPlot plot to an image file and then try to use it in a subplot in Plots.jl or Makie.jl.

[duodenum96]

Thanks nonetheless and thanks for the great package!