Skip to content

updated assignment1.sql file and added section 1.png #1

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
MuradAhmed00 wants to merge 5 commits into
base: main
Choose a base branch
from
Open

updated assignment1.sql file and added section 1.png #1

Show file tree
Hide file tree
Changes from all commits
Commits
Show all changes
5 commits
Select commit Hold shift + click to select a range
1ec546a
updated assignment1.sql file and added section 1.png
MuradAhmed00 Apr 26, 2025
e5898e5
updating assignment2
MuradAhmed00 May 6, 2025
67150d8
update prompt three for section 1
MuradAhmed00 May 6, 2025
eb9a36e
adding prompts 1 and 2 for assignment 2
MuradAhmed00 May 6, 2025
4595edb
updating images
MuradAhmed00 May 6, 2025
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
Binary file added 02_activities/assignments/Assignment1_Section1.png
View file
Open in desktop
Loading
Sorry, something went wrong. Reload?
Sorry, we cannot display this file.
Sorry, this file is invalid so it cannot be displayed.
4 changes: 3 additions & 1 deletion 02_activities/assignments/Assignment2.md
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -54,7 +54,9 @@ The store wants to keep customer addresses. Propose two architectures for the CU
**HINT:** search type 1 vs type 2 slowly changing dimensions.

```
Your answer...
Type 1 is the overwrite approach. Our table is the same CUSTOMER_ADDRESS table and we would update the columns AddressID, CustomerID, Street, City, State, and Zipcode with each change/update. We wil not preserve old addresses only the most recent (MAX) one will be kept

Type 2 will retain changes through adding a new row to track the historical data. We would add rows to the type 1 approach, thus having a table that includes the following fields: AddressID, CustomerID, Street, City, State, and Zipcode with the addition of EffectiveDate and CurrentFlag, underscoring when the update was last current and whether or not it is current now. This allows us to retain the old, historical address data while leveraging the current, most up to date address information in the same table.
```

***
Expand Down
79 changes: 73 additions & 6 deletions 02_activities/assignments/assignment1.sql
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -5,20 +5,27 @@
--SELECT
/* 1. Write a query that returns everything in the customer table. */


SELECT * FROM customer;

/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */


SELECT * FROM customer
ORDER BY customer_last_name, customer_first_name
LIMIT 10;

--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1

SELECT * FROM customer_purchases
WHERE product_id = 4 OR product_id = 9;

-- option 2

SELECT *
FROM customer_purchases
WHERE product_id IN (4, 9);


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -28,30 +35,58 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
*/
-- option 1

SELECT *, quantity * cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE vendor_id >= 8 AND vendor_id <= 10;

-- option 2


SELECT *, quantity * cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE vendor_id BETWEEN 8 AND 10;

--CASE
/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz.
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed
FROM product;


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */


SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed,
CASE
WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
ELSE 0
END AS pepper_flag
FROM product;

--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */


SELECT *
FROM vendor
INNER JOIN vendor_booth_assignments
ON vendor.vendor_id = vendor_booth_assignments.vendor_id
ORDER BY vendor_name, market_date;


/* SECTION 3 */
Expand All @@ -60,14 +95,29 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */


SELECT
vendor_id,
COUNT(*) AS booth_rentals
FROM vendor_booth_assignments
GROUP BY vendor_id;

/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

SELECT
customer.customer_id,
customer_first_name,
customer_last_name,
SUM(quantity * cost_to_customer_per_qty) AS total_spent
FROM customer
INNER JOIN customer_purchases
ON customer.customer_id = customer_purchases.customer_id
GROUP BY customer.customer_id
HAVING total_spent > 2000
ORDER BY customer_last_name, customer_first_name;


--Temp Table
Expand All @@ -82,14 +132,24 @@ When inserting the new vendor, you need to appropriately align the columns to be
VALUES(col1,col2,col3,col4,col5)
*/

CREATE TABLE temp.new_vendor AS
SELECT *
FROM vendor;

INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES (10, 'Thomas''s Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');

-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.

HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */

SELECT
customer_id,
STRFTIME('%m', market_date) AS purchase_month,
STRFTIME('%Y', market_date) AS purchase_year
FROM customer_purchases;


/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Expand All @@ -98,3 +158,10 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */

SELECT
customer_id,
SUM(quantity * cost_to_customer_per_qty) AS total_spent
FROM customer_purchases
WHERE STRFTIME('%m', market_date) = '04'
AND STRFTIME('%Y', market_date) = '2022'
GROUP BY customer_id;
108 changes: 99 additions & 9 deletions 02_activities/assignments/assignment2.sql
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -20,6 +20,11 @@ The `||` values concatenate the columns into strings.
Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed.
All the other rows will remain the same.) */

SELECT
product_name || ', ' || COALESCE(product_size, '')
|| ' (' || COALESCE(product_qty_type, 'unit') || ')'
AS details
FROM product;


--Windowed Functions
Expand All @@ -32,18 +37,33 @@ each new market date for each customer, or select only the unique market dates p
(without purchase details) and number those visits.
HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */


SELECT *, ROW_NUMBER()
OVER (PARTITION BY customer_id ORDER BY market_date)
AS visit_number
FROM customer_purchases;

/* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1,
then write another query that uses this one as a subquery (or temp table) and filters the results to
only the customer’s most recent visit. */

WITH recent_visit AS (SELECT *,
ROW_NUMBER()
OVER (PARTITION BY customer_id ORDER BY market_date DESC)
AS ranked
FROM customer_purchases
)
SELECT *
FROM recent_visit
WHERE ranked = 1;


/* 3. Using a COUNT() window function, include a value along with each row of the
customer_purchases table that indicates how many different times that customer has purchased that product_id. */


SELECT*, COUNT(*)
OVER (PARTITION BY customer_id, product_id)
AS time_purchase
FROM customer_purchases;

-- String manipulations
/* 1. Some product names in the product table have descriptions like "Jar" or "Organic".
Expand All @@ -57,11 +77,26 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for

Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */


SELECT product_name,
CASE
WHEN INSTR(product_name, '-') > 0
THEN TRIM(
SUBSTR(product_name,INSTR(product_name, '-') + 1))
ELSE NULL
END AS description
FROM product;

/* 2. Filter the query to show any product_size value that contain a number with REGEXP. */


SELECT product_name, product_size,
CASE
WHEN INSTR(product_name, '-') > 0
THEN TRIM(
SUBSTR(product_name,INSTR(product_name, '-') + 1))
ELSE NULL
END AS description
FROM product
WHERE product_size REGEXP '[0-9]';

-- UNION
/* 1. Using a UNION, write a query that displays the market dates with the highest and lowest total sales.
Expand All @@ -73,6 +108,25 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
3) Query the second temp table twice, once for the best day, once for the worst day,
with a UNION binding them. */

WITH daily_sales AS (
SELECT market_date, SUM(quantity * cost_to_customer_per_qty) AS total_sales
FROM customer_purchases
GROUP BY market_date),
ranked_sales AS (
SELECT market_date, total_sales,
RANK() OVER (ORDER BY total_sales ASC) AS rank_low,
RANK() OVER (ORDER BY total_sales DESC) AS rank_high
FROM daily_sales
)
SELECT market_date, total_sales,'worst' AS day_type
FROM ranked_sales
WHERE rank_low = 1

UNION

SELECT market_date, total_sales,'best' AS day_type
FROM ranked_sales
WHERE rank_high = 1;



Expand All @@ -89,27 +143,56 @@ Think a bit about the row counts: how many distinct vendors, product names are t
How many customers are there (y).
Before your final group by you should have the product of those two queries (x*y). */

WITH vendor_products AS (
SELECT vi.vendor_id, vi.product_id, vi.original_price
FROM vendor_inventory AS vi),

joined AS (
SELECT vp.vendor_id, vp.product_id, vp.original_price, c.customer_id
FROM vendor_products AS vp
CROSS JOIN customer AS c)

SELECT v.vendor_name, p.product_name, SUM(5 * e.original_price) AS money_made
FROM joined AS e
JOIN vendor AS v ON v.vendor_id = e.vendor_id
JOIN product AS p ON p.product_id = e.product_id
GROUP BY v.vendor_name, p.product_name
ORDER BY v.vendor_name, p.product_name;

-- INSERT
/*1. Create a new table "product_units".
This table will contain only products where the `product_qty_type = 'unit'`.
It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.
Name the timestamp column `snapshot_timestamp`. */


CREATE TABLE product_units AS
SELECT *, CURRENT_TIMESTAMP AS snapshot_timestamp
FROM product
WHERE product_qty_type = 'unit';

/*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp).
This can be any product you desire (e.g. add another record for Apple Pie). */


INSERT INTO product_units
(product_id,
product_name,
product_size,
product_category_id,
product_qty_type,
snapshot_timestamp)
VALUES (7, 'Apple Pie', '12"', 3, 'unit', CURRENT_TIMESTAMP);

-- DELETE
/* 1. Delete the older record for the whatever product you added.

HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/


DELETE FROM product_units
WHERE product_id = 7
AND snapshot_timestamp <>
(SELECT MAX(snapshot_timestamp)
FROM product_units
WHERE product_id = 7);

-- UPDATE
/* 1.We want to add the current_quantity to the product_units table.
Expand All @@ -128,6 +211,13 @@ Finally, make sure you have a WHERE statement to update the right row,
you'll need to use product_units.product_id to refer to the correct row within the product_units table.
When you have all of these components, you can run the update statement. */

ALTER TABLE product_units
ADD current_quantity INT;



UPDATE product_units
SET current_quantity = COALESCE(
(SELECT vi.quantity
FROM vendor_inventory AS vi
WHERE vi.product_id = product_units.product_id
ORDER BY vi.market_date DESC
LIMIT 1),0);
Binary file added 02_activities/assignments/assignment2_prompt1.png
View file
Open in desktop
Loading
Sorry, something went wrong. Reload?
Sorry, we cannot display this file.
Sorry, this file is invalid so it cannot be displayed.
Binary file added 02_activities/assignments/assignment2_prompt2.png
View file
Open in desktop
Loading
Sorry, something went wrong. Reload?
Sorry, we cannot display this file.
Sorry, this file is invalid so it cannot be displayed.
Binary file added 05_src/sql/farmersmarket.db-journal
View file
Open in desktop
Binary file not shown.