Add 2q fractional gates to the ConsolidateBlocks transpiler pass

[ShellyGarion]

Summary

With the introduction of new 2q-fractional gates, such as RZZGate as part of the QPU, we add them to the ConsolidateBlocks transpiler pass.
https://www.ibm.com/quantum/blog/fractional-gates

This PR should close #13428

Details and comments

Note that this PR may be eventually superseded by #13419

[qiskit-bot]

One or more of the following people are relevant to this code:

• @Qiskit/terra-core

[ShellyGarion]

The only test currently failing is:

qiskit/test/python/transpiler/test_consolidate_blocks.py

Line 567 in 682e2d3

def test_no_kak_gates_in_preset_pm(self, opt_level):

This test was added in #13450 to handle issue #13438, and I wonder if we should remove it.
@mtreinish @ElePT - what's your opinion?

the original circuit is:

        ┌────┐   
q_0: ─■─┤ √X ├─■─
      │ ├────┤ │ 
q_1: ─■─┤ √X ├─■─
        └────┘   

the circuit after basis translation is:

global phase: 7π/4
               ┌──────────┐   ┌────┐            ┌──────────┐
q_0: ─■────────┤ Rz(-π/2) ├───┤ √X ├───■────────┤ Rz(-π/2) ├
      │ZZ(π/2) ├──────────┤┌──┴────┴─┐ │ZZ(π/2) ├──────────┤
q_1: ─■────────┤ Rz(-π/2) ├┤ Rx(π/2) ├─■────────┤ Rz(-π/2) ├
               └──────────┘└─────────┘          └──────────┘

The circuit after optimization_level 2 or 3 transpilation is:

global phase: 3π/2
     ┌──────────┐┌───────┐           ┌──────────┐┌────────┐           »
q_0: ┤ Rz(-π/2) ├┤ Rx(π) ├─■─────────┤ Rx(-π/2) ├┤ Rz(-π) ├─■─────────»
     ├─────────┬┘└───────┘ │ZZ(-π/2) ├──────────┤├────────┤ │ZZ(-π/2) »
q_1: ┤ Rz(π/2) ├───────────■─────────┤ Rx(-π/2) ├┤ Rz(-π) ├─■─────────»
     └─────────┘                     └──────────┘└────────┘           »
«     ┌──────────┐
«q_0: ┤ Rz(-π/2) ├
«     ├─────────┬┘
«q_1: ┤ Rz(π/2) ├─
«     └─────────┘ 

The reason that this circuit is being consolidated is that it originally contains CZ gates. If it had contained only RZZ gates, then it would not had been consolidated.

I think that it would be better handled in #13419 (which should take into account the 1-qubit gates).

[ShellyGarion]

Note that due to the TwoQubitControlledUDecomposer synthesis algorithm, the synthesized circuit is:

q_0: ──────────■──────────────────
     ┌───────┐ │ZZ(-0.3) ┌───────┐
q_1: ┤ Rx(π) ├─■─────────┤ Rx(π) ├
     └───────┘           └───────┘

and not just RZZGate(0.3)