1328) Break a Palindrome.py

class Solution:
    def breakPalindrome(self, palindrome: str) -> str:
         
        
        for i in range(len(palindrome)//2):
                if palindrome[i]!='a':
                    return palindrome[:i]+'a'+palindrome[i+1:]
                        
        return palindrome[:-1]+'b' if len(palindrome)>1 else ""