Find all valid combinations of k
numbers that sum up to n
such that the following conditions are true:
- Only numbers
1
through9
are used. - Each number is used at most once.
Return a list of all possible valid combinations. The list must not contain the same combination twice, and the combinations may be returned in any order.
Example 1:
Input: k = 3, n = 7 Output: [[1,2,4]] Explanation: 1 + 2 + 4 = 7 There are no other valid combinations.
Example 2:
Input: k = 3, n = 9 Output: [[1,2,6],[1,3,5],[2,3,4]] Explanation: 1 + 2 + 6 = 9 1 + 3 + 5 = 9 2 + 3 + 4 = 9 There are no other valid combinations.
Example 3:
Input: k = 4, n = 1 Output: [] Explanation: There are no valid combinations. Using 4 different numbers in the range [1,9], the smallest sum we can get is 1+2+3+4 = 10 and since 10 > 1, there are no valid combination.
Constraints:
2 <= k <= 9
1 <= n <= 60
class Solution {
public:
vector<vector<int>> combinationSum3(int k, int n) {
vector<vector<int>> ans;
vector<int> comb;
combination(ans,comb,k,1,n);
return ans;
}
void combination(vector<vector<int>> &ans,vector<int> &comb,int &k,int st,int n){
if(comb.size()==k){
if(!n)
ans.push_back(comb);
return;
}
for(int i=st;i<10;i++){
comb.push_back(i);
combination(ans,comb,k,i+1,n-i);
comb.pop_back();
}
}
};