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if is_holiday(today): # do nothing if holiday return elif datetime.date.today().weekday() in [5, 0]: return
此处的[5,0] 应该是[5,6]吧?
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tushare/barfeed.py
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if is_holiday(today): # do nothing if holiday
return
elif datetime.date.today().weekday() in [5, 0]:
return
此处的[5,0] 应该是[5,6]吧?
The text was updated successfully, but these errors were encountered: