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merge_2_bst.cc
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merge_2_bst.cc
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> getAllElements(TreeNode* root1, TreeNode* root2) {
std::vector<int> p;
std::vector<int> q;
std::vector<int> v;
InOrder(root1, p);
InOrder(root2, q);
if (q.empty())
return p;
else if
(p.empty()) return q;
else
Merge(p, q, v);
return v;
}
private:
void InOrder(TreeNode *root, std::vector<int> &v) {
if (!root)
return;
if (root->left)
InOrder(root->left, v);
v.push_back(root->val);
if (root->right)
InOrder(root->right, v);
}
void Merge(const std::vector<int> p, const std::vector<int> q, std::vector<int> &v) {
int i = 0, j = 0;
while (i < p.size() || j < q.size()) {
if (i == p.size() || j == q.size())
break;
if (p[i] <= q[j])
v.push_back(p[i++]);
else
v.push_back(q[j++]);
}
if (i < p.size())
while (i < p.size())
v.push_back(p[i++]);
else
while (j < q.size())
v.push_back(q[j++]);
}
};