more about for loops.ipynb

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   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Revision"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1\n",
      "2\n",
      "3\n",
      "4\n"
     ]
    }
   ],
   "source": [
    "for i in range(1,5):\n",
    "    print(i)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# shorthand to use range function"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "0\n",
      "1\n",
      "2\n"
     ]
    }
   ],
   "source": [
    "#range(n) gives numbers upto n excluding n\n",
    "for i in range(3):\n",
    "    print(i)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "apple\n",
      "banana\n",
      "microsoft\n"
     ]
    }
   ],
   "source": [
    "a=[\"apple\",\"banana\",\"microsoft\"]\n",
    "for element in a:\n",
    "    print(element)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "apple\n",
      "banana\n",
      "microsoft\n"
     ]
    }
   ],
   "source": [
    "#range of length of a has numbers till the end of the list \"a\"\n",
    "for i in range(len(a)):\n",
    "    print(a[i])"
   ]
  },
  {
   "cell_type": "raw",
   "metadata": {},
   "source": [
    "1st method is quite easy but 2nd method can be used where index of the element has some further task"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "apple\n",
      "banana\n",
      "banana\n",
      "microsoft\n",
      "microsoft\n",
      "microsoft\n"
     ]
    }
   ],
   "source": [
    "for i in range(len(a)):\n",
    "    for j in range(i+1):\n",
    "        #i=0 ->j=0\n",
    "        #i=1 ->j=0,1\n",
    "        #i=2 ->j=0,1,2\n",
    "        print(a[i])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
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