1295-find-numbers-with-even-number-of-digits.py

"""
Problem Link: https://leetcode.com/problems/find-numbers-with-even-number-of-digits/

Given an array nums of integers, return how many of them contain an even number of digits.
 
Example 1:
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:
Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.
 
Constraints:
1 <= nums.length <= 500
1 <= nums[i] <= 10^5
"""
class Solution:
    def findNumbers(self, nums: List[int]) -> int:
      return sum(self.number_of_digits(number) for number in nums)        
        
        
    def number_of_digits(self, n):
      count = 0
      while n:
        count += 1
        n //= 10
      return 1 if count % 2 == 0 else 0