2094.finding-3-digit-even-numbers.py

#
# @lc app=leetcode id=2094 lang=python3
#
# [2094] Finding 3-Digit Even Numbers
#
# https://leetcode.com/problems/finding-3-digit-even-numbers/description/
#
# algorithms
# Easy (63.19%)
# Likes:    850
# Dislikes: 277
# Total Accepted:    39.9K
# Total Submissions: 63.2K
# Testcase Example:  '[2,1,3,0]'
#
# You are given an integer array digits, where each element is a digit. The
# array may contain duplicates.
# 
# You need to find all the unique integers that follow the given
# requirements:
# 
# 
# The integer consists of the concatenation of three elements from digits in
# any arbitrary order.
# The integer does not have leading zeros.
# The integer is even.
# 
# 
# For example, if the given digits were [1, 2, 3], integers 132 and 312 follow
# the requirements.
# 
# Return a sorted array of the unique integers.
# 
# 
# Example 1:
# 
# 
# Input: digits = [2,1,3,0]
# Output: [102,120,130,132,210,230,302,310,312,320]
# Explanation: All the possible integers that follow the requirements are in
# the output array. 
# Notice that there are no odd integers or integers with leading zeros.
# 
# 
# Example 2:
# 
# 
# Input: digits = [2,2,8,8,2]
# Output: [222,228,282,288,822,828,882]
# Explanation: The same digit can be used as many times as it appears in
# digits. 
# In this example, the digit 8 is used twice each time in 288, 828, and 882. 
# 
# 
# Example 3:
# 
# 
# Input: digits = [3,7,5]
# Output: []
# Explanation: No even integers can be formed using the given digits.
# 
# 
# 
# Constraints:
# 
# 
# 3 <= digits.length <= 100
# 0 <= digits[i] <= 9
# 
# 
#

# @lc code=start
class Solution:
    def findEvenNumbers(self, digits: List[int]) -> List[int]:
        
# @lc code=end