Merge branch 'main' into ohchaeyeon

Author: oh-chaeyeon

JooKangSan/[week2]stack/ I_hate_English.js

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+function solution(numbers) {
+  const nums = [
+    "zero",
+    "one",
+    "two",
+    "three",
+    "four",
+    "five",
+    "six",
+    "seven",
+    "eight",
+    "nine",
+  ];
+  let answer = numbers;
+
+  for (let i = 0; i < nums.length; i++) {
+    answer = answer.replace(nums[i], i);
+  }
+
+  return Number(answer);
+}

JooKangSan/[week2]stack/Calculating_Strings.js

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+function solution(my_string) {
+  let arr = my_string.split(' ');
+  let result = Number(arr[0]);
+  
+  for(let i = 1; i < arr.length; i += 2) {
+      const sign = arr[i];
+      const num = Number(arr[i + 1]);
+      
+      if(sign === '+') {
+          result += num;
+      }
+      if(sign === '-') {
+          result -= num;
+      }
+  }
+  
+  return result;
+}

JooKangSan/[week2]stack/Correct_Parentheses.js

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+function solution(s){
+  const stack = [];
+ 
+ for (let i = 0 ; i < s.length ; i++) {
+     if(s[i] == '('){
+         stack.push(')');
+     }else if(s[i] == '['){
+         stack.push(']');
+     }else if(s[i] == '{'){
+         stack.push('}');
+     }else{
+         if (s[i] !== stack.pop()) {
+             return false;
+         }
+     }
+ }
+ return stack.length === 0;
+}

JooKangSan/[week2]stack/Crane_Claw_Game.js

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+function solution(board, moves) {
+  let answer = 0;
+  let stack = [];
+  
+  for(let move of moves) {
+      let col = move - 1;
+      
+      for(let row = 0; row < board.length; row++) {
+          if(board[row][col] !== 0) {
+              let doll = board[row][col];
+              board[row][col] = 0;
+              if(stack[stack.length - 1] === doll) {
+                  stack.pop();
+                  answer += 2;
+              } else {
+                  stack.push(doll);
+              }
+              break;
+          }
+      }
+  }
+  
+  return answer;
+}

JooKangSan/[week2]stack/Ctrl_Z.js

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+function solution(s) {
+  let stack = [];
+  let arr = s.split(" ");
+  
+  for(let i = 0; i < arr.length; i++) {
+      if(arr[i] === "Z") {
+          stack.pop();
+      } else {
+          stack.push(Number(arr[i]));
+      }
+  }
+  
+  let sum = 0;
+  for(let i = 0; i < stack.length; i++) {
+      sum += stack[i];
+  }
+  
+  return sum;
+}

JooKangSan/[week2]stack/Dart_Game.js

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+function solution(dartResult) {
+  let scores = [];
+  let currentNumber = '';
+  
+  for(let i = 0; i < dartResult.length; i++) {
+      let char = dartResult[i];
+      
+      if(!isNaN(char)) {
+          currentNumber += char;
+      }
+      else if(char === 'S' || char === 'D' || char === 'T') {
+          let score = Number(currentNumber);
+          
+          if(char === 'D') score = Math.pow(score, 2);
+          if(char === 'T') score = Math.pow(score, 3);
+          
+          scores.push(score);
+          currentNumber = '';
+      }
+      else {
+          if(char === '*') {
+              scores[scores.length-1] *= 2;
+              if(scores.length > 1) {
+                  scores[scores.length-2] *= 2;
+              }
+          }
+          else if(char === '#') {
+              scores[scores.length-1] *= -1;
+          }
+      }
+  }
+  
+  return scores.reduce((acc, cur) => acc + cur, 0);
+}

JooKangSan/[week2]stack/Reverse_String.js

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+function solution(my_string) {
+  return my_string.split('').reverse().join('');
+}

JooKangSan/[week2]stack/stack.md

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+# JavaScript Stack 알고리즘
+
+## 1. 스택의 기본 구현
+```javascript
+class Stack {
+    constructor() {
+        this.items = [];
+        this.count = 0;
+    }
+
+    // 요소 추가
+    push(element) {
+        this.items[this.count] = element;
+        this.count++;
+        return this.count - 1;
+    }
+
+    // 요소 제거
+    pop() {
+        if(this.count === 0) return undefined;
+        
+        this.count--;
+        const result = this.items[this.count];
+        delete this.items[this.count];
+        return result;
+    }
+
+    // 최상단 요소 확인
+    peek() {
+        return this.items[this.count - 1];
+    }
+
+    // 스택이 비어있는지 확인
+    isEmpty() {
+        return this.count === 0;
+    }
+
+    // 스택 크기 반환
+    size() {
+        return this.count;
+    }
+
+    // 스택 초기화
+    clear() {
+        this.items = [];
+        this.count = 0;
+        return this;
+    }
+}
+```
+
+## 2. 스택을 활용한 알고리즘 예시
+
+### 2.1 괄호 매칭 확인
+```javascript
+function isValidParentheses(str) {
+    const stack = [];
+    const brackets = {
+        ')': '(',
+        '}': '{',
+        ']': '['
+    };
+
+    for (let char of str) {
+        if (!brackets[char]) {
+            stack.push(char);
+        } else {
+            if (stack.pop() !== brackets[char]) return false;
+        }
+    }
+
+    return stack.length === 0;
+}
+```
+
+### 2.2 후위 표기식 계산
+```javascript
+function evaluatePostfix(expr) {
+    const stack = [];
+    
+    for(let token of expr.split(' ')) {
+        if(!isNaN(token)) {
+            stack.push(Number(token));
+        } else {
+            const b = stack.pop();
+            const a = stack.pop();
+            
+            switch(token) {
+                case '+': stack.push(a + b); break;
+                case '-': stack.push(a - b); break;
+                case '*': stack.push(a * b); break;
+                case '/': stack.push(a / b); break;
+            }
+        }
+    }
+    
+    return stack[0];
+}
+```
+
+### 2.3 히스토리 관리 (실행 취소/재실행)
+```javascript
+class UndoRedoStack {
+    constructor() {
+        this.undoStack = [];
+        this.redoStack = [];
+    }
+
+    // 작업 수행
+    doAction(action) {
+        this.undoStack.push(action);
+        this.redoStack = []; // 새 작업 시 redo 스택 초기화
+    }
+
+    // 실행 취소
+    undo() {
+        if (this.undoStack.length === 0) return null;
+        const action = this.undoStack.pop();
+        this.redoStack.push(action);
+        return action;
+    }
+
+    // 재실행
+    redo() {
+        if (this.redoStack.length === 0) return null;
+        const action = this.redoStack.pop();
+        this.undoStack.push(action);
+        return action;
+    }
+}
+```
+
+## 3. 시간 복잡도
+
+### 기본 연산
+- Push: O(1)
+- Pop: O(1)
+- Peek: O(1)
+- isEmpty: O(1)
+- Size: O(1)
+
+### 메모리 사용
+- 공간 복잡도: O(n), n은 스택에 저장된 요소의 수
+
+## 4. 활용 사례
+
+### 4.1 함수 호출 스택
+```javascript
+function first() {
+    second();
+    console.log('first');
+}
+
+function second() {
+    third();
+    console.log('second');
+}
+
+function third() {
+    console.log('third');
+}
+
+first();
+// 출력:
+// third
+// second
+// first
+```
+
+### 4.2 웹 브라우저 방문 기록
+```javascript
+class BrowserHistory {
+    constructor() {
+        this.history = [];
+        this.current = -1;
+    }
+
+    visit(url) {
+        this.current++;
+        this.history[this.current] = url;
+        this.history.length = this.current + 1;
+    }
+
+    back() {
+        if (this.current > 0) {
+            this.current--;
+            return this.history[this.current];
+        }
+        return null;
+    }
+
+    forward() {
+        if (this.current < this.history.length - 1) {
+            this.current++;
+            return this.history[this.current];
+        }
+        return null;
+    }
+}
+```
+
+## 5. 주의사항
+
+1. 메모리 관리
+   - 스택 크기 제한 고려
+   - 메모리 누수 방지를 위한 참조 해제
+
+2. 에러 처리
+   - 빈 스택에서의 pop 연산 처리
+   - 스택 오버플로우 방지
+
+3. 성능 최적화
+   - 배열 크기 동적 조정 최소화
+   - 불필요한 복사 연산 방지

JustDevRae/Stack/control_Z.js

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+function solution(s) {
+  var answer = 0;
+  let Z = 0;
+  const controlArray = s.split(" ");
+  for (let i = 0; i < controlArray.length; i++) {
+    if (controlArray[i] == "Z") {
+      answer -= Z;
+      continue;
+    }
+    answer += Number(controlArray[i]);
+    Z = Number(controlArray[i]);
+  }
+
+  return answer;
+}