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| 1 | +using LeetCode.Challenges.Problems00xx.N_0083_RemoveDuplicatesFromSortedList; |
| 2 | +using Shouldly; |
| 3 | +using Xunit; |
| 4 | + |
| 5 | +namespace LeetCode.Challenges.UnitTests.Problems00xx.N_0083_RemoveDuplicatesFromSortedList; |
| 6 | + |
| 7 | +public class SolutionTests |
| 8 | +{ |
| 9 | + [Theory] |
| 10 | + [MemberData(nameof(TestCases))] |
| 11 | + public void GivenListNode_WhenDeleteDuplicates_ThenResultAsExpected(ListNode? head, ListNode? expectedResult) |
| 12 | + { |
| 13 | + Solution.DeleteDuplicates(head).ShouldBeEquivalentTo(expectedResult); |
| 14 | + } |
| 15 | + |
| 16 | + public static IEnumerable<object[]> TestCases() |
| 17 | + { |
| 18 | + // Case 1: List with duplicates [1, 1, 2] -> [1, 2] |
| 19 | + var head = new ListNode(1, new ListNode(1, new ListNode(2))); |
| 20 | + var expectedResult = new ListNode(1, new ListNode(2)); |
| 21 | + yield return [head, expectedResult]; |
| 22 | + |
| 23 | + // Case 2: List with all elements identical [1, 1, 1] -> [1] |
| 24 | + head = new ListNode(1, new ListNode(1, new ListNode(1))); |
| 25 | + expectedResult = new ListNode(1); |
| 26 | + yield return [head, expectedResult]; |
| 27 | + |
| 28 | + // Case 3: List with interspersed duplicates [1, 2, 2, 3] -> [1, 2, 3] |
| 29 | + head = new ListNode(1, new ListNode(2, new ListNode(2, new ListNode(3)))); |
| 30 | + expectedResult = new ListNode(1, new ListNode(2, new ListNode(3))); |
| 31 | + yield return [head, expectedResult]; |
| 32 | + |
| 33 | + // Case 4: List with trailing duplicates [1, 2, 3, 3, 4] -> [1, 2, 3, 4] |
| 34 | + head = new ListNode(1, new ListNode(2, new ListNode(3, new ListNode(3, new ListNode(4))))); |
| 35 | + expectedResult = new ListNode(1, new ListNode(2, new ListNode(3, new ListNode(4)))); |
| 36 | + yield return [head, expectedResult]; |
| 37 | + |
| 38 | + // Case 5: List with no duplicates [1, 2, 3, 4, 5] -> [1, 2, 3, 4, 5] |
| 39 | + head = new ListNode(1, new ListNode(2, new ListNode(3, new ListNode(4, new ListNode(5))))); |
| 40 | + expectedResult = new ListNode(1, new ListNode(2, new ListNode(3, new ListNode(4, new ListNode(5))))); |
| 41 | + yield return [head, expectedResult]; |
| 42 | + |
| 43 | + // Case 6: Single-node list [1] -> [1] |
| 44 | + head = new ListNode(1); |
| 45 | + expectedResult = new ListNode(1); |
| 46 | + yield return [head, expectedResult]; |
| 47 | + |
| 48 | + // Case 7: Empty list -> Empty list |
| 49 | + head = null; |
| 50 | + expectedResult = null; |
| 51 | + yield return [head!, expectedResult!]; |
| 52 | + |
| 53 | + // Case 8: Complex list with duplicates [1, 1, 1, 2, 2, 3, 3] -> [1, 2, 3] |
| 54 | + head = new ListNode( |
| 55 | + 1, new ListNode( |
| 56 | + 1, new ListNode( |
| 57 | + 1, new ListNode( |
| 58 | + 2, new ListNode( |
| 59 | + 2, new ListNode( |
| 60 | + 3, new ListNode(3))))))); |
| 61 | + |
| 62 | + expectedResult = new ListNode(1, new ListNode(2, new ListNode(3))); |
| 63 | + yield return [head, expectedResult]; |
| 64 | + } |
| 65 | +} |
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