You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
In Lemma 4.3, the easy direction (Exercise 29) can easily be proved. However, the other direction needs additional conditions, otherwise, it's not correct. For example, consider f(x) = -√x for x ≥ 0. The function and the domain are convex, but there is no subgradient at 0
The text was updated successfully, but these errors were encountered:
True, thanks for the nice catch. We should change the lemma conditions such that the sub-gradient is non-empty in the interior points of the domain as done in (Theorem 3.1.13 in Nesterov, 2004). We will update this.
In Lemma 4.3, the easy direction (Exercise 29) can easily be proved. However, the other direction needs additional conditions, otherwise, it's not correct. For example, consider f(x) = -√x for x ≥ 0. The function and the domain are convex, but there is no subgradient at 0
The text was updated successfully, but these errors were encountered: