java 范型调用问题

[sym695989697]

package com.hello.consumer;

import com.alibaba.dubbo.config.ApplicationConfig;
import com.alibaba.dubbo.config.ReferenceConfig;
import com.alibaba.dubbo.config.RegistryConfig;
import com.alibaba.dubbo.rpc.service.GenericService;

/**

• dubbo泛化调用invoker 调用入口

• @author mazhenjie

• @SInCE 2019/4/26
  */
  public class DubboGenericInvoker {

  public static void main(String[] args) {
  ApplicationConfig application = new ApplicationConfig();
  application.setName("api-generic-consumer");

   RegistryConfig registry = new RegistryConfig();
   registry.setAddress("zookeeper://172.20.30.76:2181");
  
   application.setRegistry(registry);
   
   ReferenceConfig<GenericService> reference = new ReferenceConfig<GenericService>();
   // 弱类型接口名
   reference.setInterface("calc");
   reference.setVersion("1.0.0");
   reference.setGroup("dubbo");
   // 声明为泛化接口
   reference.setGeneric(true);
   reference.setApplication(application);
  
   // 用com.alibaba.dubbo.rpc.service.GenericService可以替代所有接口引用
   GenericService genericService = reference.get();
  
    Object name = genericService.$invoke("multi2", new String[] {String.class.getName()}, new Object[]{"2"});
   System.out.println(name);
  

  }
  }

---

直接进
if not handler:
logging.warning(f'no handler for {msg.service_name}.{msg.method_name}')
continue
针对这个如何修改？？？在线等

[feiyuw]

@sym695989697 拖得有点久，泛型这块之前没有作处理，我在decode这边加了一些代码，目前简单类型能够跑通，见
3b925ff