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CourseScheduleII.java
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package leetcode;
import java.util.LinkedList;
import java.util.Queue;
/**
* Project Name : Leetcode
* Package Name : leetcode
* File Name : CourseScheduleII
* Creator : Edward
* Date : Dec, 2017
* Description : 210. Course Schedule II
*/
public class CourseScheduleII {
/**
* There are a total of n courses you have to take, labeled from 0 to n - 1.
Some courses may have prerequisites, for example to take course 0 you have to first take course 1,
which is expressed as a pair: [0,1]
Given the total number of courses and a list of prerequisite pairs, return the resing of courses you should
take to finish all courses.
There may be multiple correct ress, you just need to return one of them. If it is impossible to finish all courses,
return an empty array.
For example:
2, [[1,0]]
There are a total of 2 courses to take. To take course 1 you should have finished course 0. So the correct course res
is [0,1]
4, [[1,0],[2,0],[3,1],[3,2]]
There are a total of 4 courses to take. To take course 3 you should have finished both courses 1 and 2.
Both courses 1 and 2 should be taken after you finished course 0. So one correct course res is [0,1,2,3].
Another correct resing is[0,2,1,3].
-> 1 ->
0 3
-> 2 ->
入度 = 0 => BFS
0 : 0
1 : 0
2 : 0
3 : 0
queue : 3
res : 0,1,2,3
time : O(V + E)
space : O(n)
* @param numCourses
* @param prerequisites
* @return
*/
public int[] findres(int numCourses, int[][] prerequisites) {
int[] indegree = new int[numCourses];
int[] res = new int[numCourses];
int k = 0;
for (int[] pair : prerequisites) {
indegree[pair[0]]++;
}
Queue<Integer> queue = new LinkedList<>();
for (int i = 0; i < indegree.length; i++) {
if (indegree[i] == 0) {
queue.offer(i);
res[k++] = i;
}
}
while (!queue.isEmpty()) {
int pre = queue.poll();
for (int[] pair : prerequisites) {
if (pair[1] == pre) {
indegree[pair[0]]--;
if (indegree[pair[0]] == 0) {
queue.offer(pair[0]);
res[k++] = pair[0];
}
}
}
}
return (k == numCourses) ? res : new int[0];
}
}