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PyStrIterator.cpp
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68 lines (54 loc) · 1.75 KB
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/*
* File: PyStrIterator.cpp
* Author: kent
* (c) 2013
* Created on February 28, 2013, 9:55 AM
*
* License:
* Please read the LICENSE file in this distribution for details regarding
* the licensing of this code. This code is freely available for educational
* use. THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND.
*
* Description:
* See the associated header file for a description of the purpose of this
* class. Implementation details are provided here. Read below for
* any specific details.
*
*/
#include "PyStrIterator.h"
#include "PyException.h"
#include "PyStr.h"
#include <sstream>
using namespace std;
PyStrIterator::PyStrIterator(PyStr* str) : PyObject() {
this->str = str;
this->index = 0;
dict["__iter__"] = (PyObject* (PyObject::*)(vector<PyObject*>*)) (&PyStrIterator::__iter__);
dict["__next__"] = (PyObject* (PyObject::*)(vector<PyObject*>*)) (&PyStrIterator::__next__);
}
PyStrIterator::~PyStrIterator() {
}
PyType* PyStrIterator::getType() {
return PyTypes[PyStrIteratorType];
}
string PyStrIterator::toString() {
ostringstream s;
s << "<str_iterator object at " << this << ">";
return s.str();
}
PyObject* PyStrIterator::__iter__(vector<PyObject*>* args) {
ostringstream msg;
if (args->size() != 0) {
msg << "TypeError: expected 0 arguments, got " << args->size();
throw new PyException(PYWRONGARGCOUNTEXCEPTION,msg.str());
}
return this;
}
PyObject* PyStrIterator::__next__(vector<PyObject*>* args) {
ostringstream msg;
if (args->size() != 0) {
msg << "TypeError: expected 0 arguments, got " << args->size();
throw new PyException(PYWRONGARGCOUNTEXCEPTION,msg.str());
}
return str->charAt(index++);
}