MultiplesOf3And5.js

// eslint-disable-next-line max-len
/* Write a function that computes the sum of all numbers between 1 and some other number, inclusive, that are multiples of 3 or 5. For instance, if the supplied number is 20, the result should be 98 (3 + 5 + 6 + 9 + 10 + 12 + 15 + 18 + 20).

You may assume that the number passed in is an integer greater than 1. */

const multisum = (num) => {
  let sum = 0;
  for (let counter = 1; counter <= num; counter += 1) {
    if (counter % 3 === 0 || counter % 5 === 0) {
      sum += counter;
    }
  }
  return sum;
};


console.log(multisum(3));       // 3
console.log(multisum(5));       // 8
console.log(multisum(10));      // 33
console.log(multisum(1000));    // 234168