word_squares.py

# Given a set of words (without duplicates),
# find all word squares you can build from them.

# A sequence of words forms a valid word square
# if the kth row and column read the exact same string,
# where 0 ≤ k < max(numRows, numColumns).

# For example, the word sequence ["ball","area","lead","lady"] forms
# a word square because each word reads the same both horizontally
# and vertically.

# b a l l
# a r e a
# l e a d
# l a d y
# Note:
# There are at least 1 and at most 1000 words.
# All words will have the exact same length.
# Word length is at least 1 and at most 5.
# Each word contains only lowercase English alphabet a-z.

# Example 1:

# Input:
# ["area","lead","wall","lady","ball"]

# Output:
# [
  # [ "wall",
    # "area",
    # "lead",
    # "lady"
  # ],
  # [ "ball",
    # "area",
    # "lead",
    # "lady"
  # ]
# ]

# Explanation:
# The output consists of two word squares. The order of output does not matter
# (just the order of words in each word square matters).

import collections

def word_squares(words):
    n = len(words[0])
    fulls = collections.defaultdict(list)
    for word in words:
        for i in range(n):
            fulls[word[:i]].append(word)

    def build(square):
        if len(square) == n:
            squares.append(square)
            return
        prefix = ""
        for k in range(len(square)):
            prefix += square[k][len(square)]
        for word in fulls[prefix]:
            build(square + [word])
    squares = []
    for word in words:
        build([word])
    return squares

dic =["area","lead","wall","lady","ball"]
print(word_squares(dic))