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01two_sum.py
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01two_sum.py
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'''
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
'''
class Solution:
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
dict ={}
for index, value in enumerate(nums):
# 值的判断
if target - value in dict:
# 之前存入的kv对的key是value, if 判断就是查找key, i.e. 有没有这个作差得到的value
return dict[target-value], index
# 因为要用enumerate中的一个查找另一个,所以存入dict的是value, 根据value查找index
dict[value] = index