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invert_a_tree.cpp
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invert_a_tree.cpp
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/*
* Invert given Binary Tree | Recursive and Iterative solution
* 1 1
* / \ / \
* 2 3 -> 3 2
* / \ / \ / \ / \
* 4 5 6 7 7 6 5 4
*
*/
#include <iostream>
#include <queue>
#include <iomanip>
struct TreeNode
{
int data;
TreeNode *left;
TreeNode *right;
TreeNode(int d)
: data{d}, left{nullptr}, right{nullptr} {}
};
void invertTreeRecur(TreeNode* root)
{
if (!root)
{
return;
}
// Swap left and right trees
//
TreeNode* temp = root->left;
root->left = root->right;
root->right = temp;
// Do this recursively for left and right sub-trees.
//
invertTreeRecur(root->left);
invertTreeRecur(root->right);
}
void invertTreeIter(TreeNode* root)
{
if (!root)
{
return;
}
std::queue<TreeNode*> nodeQueue;
nodeQueue.push(root);
while(!nodeQueue.empty())
{
TreeNode* curr = nodeQueue.front();
nodeQueue.pop();
// Swap left and right children
//
TreeNode* temp = curr->left;
curr->left = curr->right;
curr->right = temp;
if (curr->left)
{
nodeQueue.push(curr->left);
}
if (curr->right)
{
nodeQueue.push(curr->right);
}
}
}
// Prints post order traversal of tree, where level expands left to right.
//
void postOrder(TreeNode* root, int indent = 0)
{
if (root)
{
if(root->right)
{
postOrder(root->right, indent+4);
}
if (indent) {
std::cout << std::setw(indent) << ' ';
}
if (root->right)
{
std::cout<<" /\n" << std::setw(indent) << ' ';
}
std::cout<< root->data << "\n ";
if(root->left)
{
std::cout << std::setw(indent) << ' ' <<" \\\n";
postOrder(root->left, indent + 4);
}
}
}
int main()
{
TreeNode *root = new TreeNode(1);
root->left = new TreeNode(2);
root->right = new TreeNode(3);
root->left->left = new TreeNode(4);
root->left->right = new TreeNode(5);
root->right->left = new TreeNode(6);
root->right->right = new TreeNode(7);
std::cout << "Current Tree: \n";
postOrder(root);
std::cout << "\nInverting it recursively:\n";
invertTreeRecur(root);
postOrder(root);
std::cout << "\nInverting it again iteratively:\n";
invertTreeIter(root);
postOrder(root);
std::cout << std::endl;
return 0;
}