From 072aaa17b69771b78e8c1a7287eba15709f555d3 Mon Sep 17 00:00:00 2001
From: pfatheddin <156558883+pfatheddin@users.noreply.github.com>
Date: Mon, 18 Mar 2024 19:59:40 -0400
Subject: [PATCH] Update maxMinTrueFalse9.tex

https://ximera.osu.edu/mooculus/maximumsAndMinimums/exercises/exerciseList/maximumsAndMinimums/exercises/maxMinTrueFalse9

I think this can confuse students. We want them to associate decreasing with f' being negative so this statement makes them pause and doubt. So I added the sentence of what the conclusion should be to assure them that they can use the other direction of f' negative then f decreasing.
---
 maximumsAndMinimums/exercises/maxMinTrueFalse9.tex | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/maximumsAndMinimums/exercises/maxMinTrueFalse9.tex b/maximumsAndMinimums/exercises/maxMinTrueFalse9.tex
index a0a3d0ece..27ad07963 100644
--- a/maximumsAndMinimums/exercises/maxMinTrueFalse9.tex
+++ b/maximumsAndMinimums/exercises/maxMinTrueFalse9.tex
@@ -11,7 +11,7 @@
 
 	If $f$ is differentiable and decreasing on $(a,b)$, then $f'(x)<0$ on $(a,b)$
 	\begin{hint}
-Think of $f(x)=-x^3$ on $(-1,1)$. $f$ is differentiable and decreasing, but $f'(0)=0$.
+Think of $f(x)=-x^3$ on $(-1,1)$. $f$ is differentiable and decreasing, but $f'(0)=0$. So the conclusion should be $f'(x)\leq 0$ on $(a,b)$. 
 \end{hint}	
 	\begin{multipleChoice}	
 		\choice{True}