0961-N-Repeated-Element-in-Size-2N-Array.py

'''
In a array A of size 2N, there are N+1 unique elements, and exactly one of these elements is repeated N times.

Return the element repeated N times.

 

Example 1:

Input: [1,2,3,3]
Output: 3
Example 2:

Input: [2,1,2,5,3,2]
Output: 2
Example 3:

Input: [5,1,5,2,5,3,5,4]
Output: 5
 

Note:

4 <= A.length <= 10000
0 <= A[i] < 10000
A.length is even
'''
class Solution:
    def repeatedNTimes(self, A: List[int]) -> int:
        for i in range(2,len(A)):
            if A[i] == A[i-1] or A[i] == A[i-2]:
                return A[i]
        return A[0]