diff --git a/02_activities/assignments/Assignment_1_Section_1.pdf b/02_activities/assignments/Assignment_1_Section_1.pdf new file mode 100644 index 000000000..a1eb43748 Binary files /dev/null and b/02_activities/assignments/Assignment_1_Section_1.pdf differ diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql index 2e89fa7af..1d012bfa2 100644 --- a/02_activities/assignments/assignment1.sql +++ b/02_activities/assignments/assignment1.sql @@ -4,34 +4,52 @@ --SELECT /* 1. Write a query that returns everything in the customer table. */ - +SELECT * +FROM customer; /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, sorted by customer_last_name, then customer_first_ name. */ - - +SELECT * +FROM customer +ORDER BY customer_last_name, customer_first_name +LIMIT 10; --WHERE /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */ -- option 1 - +SELECT * FROM customer_purchases +WHERE product_id = 4 +OR product_id = 9; -- option 2 - - +SELECT * FROM customer_purchases +WHERE product_id IN (4, 9); /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), filtered by vendor IDs between 8 and 10 (inclusive) using either: 1. two conditions using AND 2. one condition using BETWEEN */ --- option 1 +-- option 1 X +--ALTER TABLE customer_purchases ADD price AS (quantity*cost_to_customer_per_qty); +SELECT * +FROM customer_purchases +WHERE vendor_id >=8 +AND vendor_id <= 10; +--GROUP BY customer_id, product_id, vendor_id -- option 2 +SELECT +customer_id, +product_id, +vendor_id, +SUM(quantity*cost_to_customer_per_qty) as price +FROM customer_purchases +WHERE vendor_id BETWEEN 8 AND 10; --CASE /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. @@ -39,20 +57,45 @@ Using the product table, write a query that outputs the product_id and product_n columns and add a column called prod_qty_type_condensed that displays the word “unit” if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ +SELECT product_id, product_name + + ,CASE + WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END as prod_qty_type_condensed + +FROM product; /* 2. We want to flag all of the different types of pepper products that are sold at the market. add a column to the previous query called pepper_flag that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ - +SELECT product_id, product_name + + ,CASE + WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END as prod_qty_type_condensed + + ,CASE + WHEN product_name LIKE '%pepper%' + THEN '1' + ELSE '0' + END as pepper_flag + +FROM product; --JOIN /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */ +SELECT * +FROM vendor INNER JOIN vendor_booth_assignments +ON vendor.vendor_id = vendor_booth_assignments.vendor_id +GROUP BY vendor_name, market_date; /* SECTION 3 */ @@ -60,7 +103,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t /* 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per vendor_id. */ - +SELECT vendor_id, COUNT (vendor_id) as num_of_rented +FROM vendor_booth_assignments +GROUP BY vendor_id; /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list @@ -68,7 +113,19 @@ of customers for them to give stickers to, sorted by last name, then first name. HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ +SELECT + c.customer_first_name, + c.customer_last_name, + c.customer_id, + SUM (cp.quantity*cp.cost_to_customer_per_qty) AS total_spent +FROM customer c +LEFT JOIN customer_purchases cp + ON c.customer_id = cp.customer_id + +GROUP BY c.customer_first_name, c.customer_last_name, c.customer_id +HAVING SUM (cp.quantity*cp.cost_to_customer_per_qty) > 2000 +ORDER BY c.customer_last_name, c.customer_first_name; --Temp Table /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: @@ -82,19 +139,41 @@ When inserting the new vendor, you need to appropriately align the columns to be VALUES(col1,col2,col3,col4,col5) */ +CREATE TABLE temp.new_vendor AS + +SELECT * FROM vendor; +INSERT INTO temp.new_vendor +VALUES(10, 'THomass Superfood Store', 'Fresh Focused', 'Thomas','Rosenthal') + +SELECT * FROM temp.new_vendor; -- Date /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table. HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month -and year are! */ - +and year are! */ X +SELECT + customer_id, + strftime('%m', market_date) AS month, + strftime('%Y', market_date) AS year +FROM customer_purchases + /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. Remember that money spent is quantity*cost_to_customer_per_qty. HINTS: you will need to AGGREGATE, GROUP BY, and filter... but remember, STRFTIME returns a STRING for your WHERE statement!! */ +SELECT + customer_id, + SUM (quantity*cost_to_customer_per_qty) AS total_spent + + +FROM customer_purchases +WHERE strftime('%m', market_date) = '04' +AND strftime('%Y', market_date) = '2022' + +GROUP BY customer_id diff --git a/02_activities/assignments/assignment2.pdf b/02_activities/assignments/assignment2.pdf new file mode 100644 index 000000000..2ccb84cdd Binary files /dev/null and b/02_activities/assignments/assignment2.pdf differ diff --git a/02_activities/assignments/assignment2.sql b/02_activities/assignments/assignment2.sql index 5ad40748a..6abf560b6 100644 --- a/02_activities/assignments/assignment2.sql +++ b/02_activities/assignments/assignment2.sql @@ -20,7 +20,11 @@ The `||` values concatenate the columns into strings. Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed. All the other rows will remain the same.) */ - +SELECT + (product_name || ', ') AS product_name, + COALESCE(product_size, '') AS product_size, + ' (' || COALESCE(product_qty_type, 'unit') || ')' AS product_qty +FROM product; --Windowed Functions /* 1. Write a query that selects from the customer_purchases table and numbers each customer’s @@ -32,18 +36,38 @@ each new market date for each customer, or select only the unique market dates p (without purchase details) and number those visits. HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */ - +SELECT + customer_id, + market_date, + row_number() OVER (PARTITION BY customer_id ORDER BY market_date) AS visit_number +FROM customer_purchases +ORDER BY customer_id, market_date /* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1, then write another query that uses this one as a subquery (or temp table) and filters the results to only the customer’s most recent visit. */ - +SELECT + customer_id, + market_date +FROM ( + SELECT + customer_id, + market_date, + row_number() OVER (PARTITION BY customer_id ORDER BY market_date DESC) AS visit_number +FROM customer_purchases +) AS ranked_visits +WHERE visit_number = 1 /* 3. Using a COUNT() window function, include a value along with each row of the customer_purchases table that indicates how many different times that customer has purchased that product_id. */ - +SELECT + customer_id, + product_id, + market_date, + COUNT(*) OVER (PARTITION BY customer_id, product_id) AS product_purchase_count +FROM customer_purchases -- String manipulations /* 1. Some product names in the product table have descriptions like "Jar" or "Organic". @@ -57,11 +81,26 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */ - +SELECT + product_name, + CASE + WHEN INSTR(product_name, '-') > 0 + THEN TRIM(substr(product_name, INSTR(product_name, '-') +1)) + ELSE NULL + END AS description +FROM product /* 2. Filter the query to show any product_size value that contain a number with REGEXP. */ - +SELECT + product_size, + CASE + WHEN INSTR(product_size, '-') > 0 + THEN TRIM(substr(product_size, INSTR(product_size, '-') +1)) + ELSE NULL + END AS description +FROM product +WHERE product_size REGEXP '[0-9]' -- UNION /* 1. Using a UNION, write a query that displays the market dates with the highest and lowest total sales. @@ -73,8 +112,36 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling 3) Query the second temp table twice, once for the best day, once for the worst day, with a UNION binding them. */ +CREATE TABLE temp.sales_values_by_date AS +SELECT + market_date, + SUM(original_price) as total_sales +FROM vendor_inventory +GROUP BY market_date; +CREATE TABLE temp.best_worst_sales_values_by_date AS +SELECT + market_date, + total_sales, +rank() OVER (ORDER BY total_sales DESC) as [best], +rank() OVER (ORDER BY total_sales ASC) as [worst] +FROM sales_values_by_date; + +SELECT + market_date, + total_sales, + 'Best Day' AS sales_type +FROM temp.best_worst_sales_values_by_date +WHERE best = 1 +UNION + +SELECT + market_date, + total_sales, + 'Worst Day' AS sales_type +FROM temp.best_worst_sales_values_by_date +WHERE worst = 1 /* SECTION 3 */ @@ -89,7 +156,15 @@ Think a bit about the row counts: how many distinct vendors, product names are t How many customers are there (y). Before your final group by you should have the product of those two queries (x*y). */ - +SELECT + v.vendor_name, + p.product_name, + count(c.customer_id)* 5 * vi.original_price AS vendor_revenue +FROM vendor_inventory vi +JOIN vendor v ON vi.vendor_id = v.vendor_id +JOIN product p ON vi.product_id = p.product_id +CROSS JOIN customer c +GROUP BY v.vendor_name, p.product_name, vi.original_price -- INSERT /*1. Create a new table "product_units". @@ -97,19 +172,28 @@ This table will contain only products where the `product_qty_type = 'unit'`. It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`. Name the timestamp column `snapshot_timestamp`. */ - +CREATE TABLE product_unit AS +SELECT + *, + CURRENT_TIMESTAMP AS snapshot_timestamp +FROM + product +WHERE + product_qty_type = 'unit' /*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp). This can be any product you desire (e.g. add another record for Apple Pie). */ - +INSERT INTO product_unit (product_id, product_name, product_size, product_qty_type,snapshot_timestamp) +VALUES (30, 'peach_pie', '500g','unit', CURRENT_TIMESTAMP) -- DELETE /* 1. Delete the older record for the whatever product you added. HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/ - +DELETE FROM product_unit +WHERE product_id = 7 -- UPDATE /* 1.We want to add the current_quantity to the product_units table. @@ -128,6 +212,19 @@ Finally, make sure you have a WHERE statement to update the right row, you'll need to use product_units.product_id to refer to the correct row within the product_units table. When you have all of these components, you can run the update statement. */ +ALTER TABLE temp.product_unit +ADD current_quantity INT; +SELECT * +FROM temp.product_unit; + +UPDATE product_unit +SET current_quantity = ( + SELECT vi.quantity + FROM vendor_inventory vi + WHERE vi.product_id = product_unit.product_id + ORDER BY vi.market_date DESC + LIMIT 1 +); diff --git a/05_src/sql/assignment1.db b/05_src/sql/assignment1.db new file mode 100644 index 000000000..6ee8eeb2f Binary files /dev/null and b/05_src/sql/assignment1.db differ diff --git a/05_src/sql/assignment1.sqbpro b/05_src/sql/assignment1.sqbpro new file mode 100644 index 000000000..e24598a8f --- /dev/null +++ b/05_src/sql/assignment1.sqbpro @@ -0,0 +1,24 @@ +
-- Reference to file "/Users/Hiro/sql/02_activities/assignments/assignment1.sql" (not supported by this version) --SELECT + c.customer_first_name, + c.customer_last_name, + c.customer_id, + SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent +FROM customer c +LEFT JOIN customer_purchases cp + ON c.customer_id = cp.customer_id +GROUP BY c.customer_first_name, c.customer_last_name, c.customer_id +HAVING SUM(cp.quantity * cp.cost_to_customer_per_qty) > 2000 +ORDER BY c.customer_last_name, c.customer_first_name;SELECT + c.customer_first_name, + c.customer_last_name, + c.customer_id, + SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent +FROM customer c +LEFT JOIN customer_purchases cp + ON c.customer_id = cp.customer_id +GROUP BY c.customer_first_name, c.customer_last_name, c.customer_id +HAVING SUM(cp.quantity * cp.cost_to_customer_per_qty) > 2000 +ORDER BY c.customer_last_name, c.customer_first_name; + + + diff --git a/05_src/sql/farmersmarket.db b/05_src/sql/farmersmarket.db index 4720f2483..d8eb765c8 100644 Binary files a/05_src/sql/farmersmarket.db and b/05_src/sql/farmersmarket.db differ diff --git a/05_src/sql/farmersmarket.sqbpro b/05_src/sql/farmersmarket.sqbpro new file mode 100644 index 000000000..1ed7639a1 --- /dev/null +++ b/05_src/sql/farmersmarket.sqbpro @@ -0,0 +1,138 @@ +
-- SELECT + +--selecting everything from customer +SELECT * +FROM customer; + +-- add a static value +SELECT 2025 as this_year, 'April' as this_month, customer_id +FROM customer; + +-- add an order by + limit +SELECT * +FROM customer +ORDER BY customer_last_name +LIMIT 10; + +--WHERE + +SELECT * FROM customer +WHERE customer_id = 1 +AND customer_id = 2; + +-- IN +SELECT * From customer_purchases +WHERE customer_id IN (3,4,5) -- only custmoer 3, 4, 5 +AND vendor_id IN (3,4,5); + +-- LLIKE +SELECT * FROM product +WHERE product_name LIKE '%pepper%'; + +-- customers with a last name starting with a +SELECT * FROM customer +WHERE customer_last_name LIKE 'a%'; + +SELECT * FROM product +WHERE product_size IS NULL +OR product_size = ''; + +SELECT * +,CASE WHEN vendor_type = 'Fresh Focused' + THEN 'Wednesday' +WHEN vendor_type = 'Prepared Foods' + THEN 'Thursday' +ELSE 'Saturday' +END as day_of_specialty +--pie day, otherwise nothing +,CASE WHEN vendor_name LIKE '%pie%' + THEN 'Wednesday' + END as only_pie_day +,CASE WHEN vendor_name = "Annie's Pies" -- double quote work, but not for all editors! + THEN 'annie is best' + END +FROM vendor--DISTINCT + +-- Without distinct 4421 rows oof various customer_id +SELECT customer_id FROM customer_purchases; + +SELECT DISTINCT customer_id FROM customer_purchases + +-- without distinctio, only we/sad 150 tiems OVER +SELECT * +FROM market_date_info; + +-- which vendor has sold product a customer +SELECT DISTINCT vendor_id +FROM customer_purchases; -- 3 rows, vendor id 7, 8 4 + +-- which vendor has sold products to a customer +SELECT DISTINCT vendor_id, product_id +FROM customer_purchases; + +-- which vencor has sold products to a customer and which product was it and to whom it was sold? +SELECT DISTINCT vendor_id, customer_id, product_id +FROM customer_purchases + +SELECT * +,CASE WHEN vendor_type = 'Fresh Focused' + THEN 'Wednesday' +WHEN vendor_type = 'Prepared Foods' + THEN 'Thursday' +ELSE 'Saturday' +END as day_of_specialty +--pie day, otherwise nothing +,CASE WHEN vendor_name LIKE '%pie%' + THEN 'Wednesday' + END as only_pie_day +,CASE WHEN vendor_name = "Annie's Pies" -- double quote work, but not for all editors! + THEN 'annie is best' + END as annie_is_king +FROM vendor + +-- INNER JOIN + +-- get prodcut names along customer_purchases +SELECT +product_name, +market_date, +customer_id, +product_id, +customer_purchases.product_id + +FROM customer_purchases +INNER JOIN product + ON customer_purchases.product_id = product.product_id/* get product names alongside customer_purchases...only products that a customer has purchased will be present */ +SELECT +product_name, -- coming from product +vendor_id, -- coming from cp...below +market_date, +customer_id, +customer_purchases.product_id + +FROM customer_purchases +INNER JOIN product + ON customer_purchases.product_id = product.product_id; + +/* which vendor has sold products to a customer AND which product was it AND to whom was it sold ? */ +SELECT DISTINCT vendor_id, +product_id, +--customer_id -- this is dissatisfying...let's have a name! +customer_first_name, +customer_last_name + +FROM customer_purchases as cp +INNER JOIN customer as c + ON cp.customer_id = c.customer_id-- LEFT JOIN + +-- there are produts being bought, but not have not? +SELECT +p.product_id, cp.product_id, +cp.*--all colums in cp TABLE + +FROM product p +LEFT JOIN customer_purchases cp + ON p.product_id = cp.product_id + +SELECT DISTINCT +p.product_id, product_name,