We have already covered the if
statement. A while
loop is exactly the same with the addition of at least one branch and a
label. It really is that simple.
To illustrate this, here is a flow chart of an if
statement (on the
left) compared to a while
loop (on the right).
The closing brace in an if
statement is indicated by the red arrow
head. This isn't a branch, the code flow simply falls through to the
statement beyond the closing brace. In the while
loop, the behavior of
the closing brace changes to be that of a branch back to just before the
evaluation of the boolean condition (the "Decision").
A new label is placed before evaluating the "Decision".
A new unconditional branch is placed after the end of the "Code Block."
For review, consider this C or C++ code:
if (a >= b) {
// CODE BLOCK
}
here is the assembly language for this if
statement:
// Assume value of a is in x0 // 1
// Assume value of b is in x1 // 2
cmp x0, x1 // 3
ble 1f // 4
// CODE BLOCK // 5
1: // 6
Now, consider this while
loop:
while (a >= b) {
// CODE BLOCK
}
Here is the code for the while
showing the addition of one new label
and one new unconditional branch:
// Assume value of a is in x0 // 1
// Assume value of b is in x1 // 2
// 3
1: cmp x0, x1 // 4
bgt 2f // 5
// CODE BLOCK // 6
b 1b // 7
// 8
2: // 9
Temporary label 2
on line 9
takes the place of the line after the
closing brace in a while
loop.
Temporary label 1
on line 4
is the end point of the red arrow in the
right hand flow chart above.
A while
loop is an extension of the if
statement. A simple if
contains one conditional branch and one label.
A while
loop contains at least two labels, one conditional branch and
one unconditional branch. We acknowledge the possibility that the
unconditional branch could be made a conditional one, but this is rarely
done in assembly language and impossible in higher level languages like
C and C++ since the branch is simply the closing }
.
(T | F) This code has a problem:
// Assume value of a is in x0 // 1
// Assume value of b is in x1 // 2
// 3
1: cmp x0, x1 // 4
b 2f // 5
// CODE BLOCK // 6
b 1b // 7
// 8
2: // 9
Answer: True - the unconditional branch on line 5
doesn't reference the
results of the cmp
that comes before it. The CODE BLOCK
will never be
executed.
(T | F) This attempt at a while
loop has a problem:
// Assume value of a is in x0 // 1
// Assume value of b is in x1 // 2
// 3
1: cmp x0, x1 // 4
ble 2f // 5
// CODE BLOCK // 6
// 7
2: // 8
Answer: True - missing a branch back to label 1
, there is no loop.