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How do you come to the amount of two packets (MTU * 2 < QCA7000 internal buffer )?
Do you mean tx ring of the driver with your suggestion?
Is the default netdev tx queue length of 100 okay?
two papers:
http://caia.swin.edu.au/reports/130121A/CAIA-TR-130121A.pdf
http://caia.swin.edu.au/reports/130417A/CAIA-TR-130417A.pdf
The discussion on netdev suggests using BQL, but at speed levels below 10mbit
two packets of buffering is enough.
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