diff --git a/C++/floodfill.cpp b/C++/floodfill.cpp
new file mode 100644
index 0000000..57d136a
--- /dev/null
+++ b/C++/floodfill.cpp
@@ -0,0 +1,66 @@
+#include<iostream> 
+using namespace std; 
+// Dimentions of myScreen. You may change
+#define M 8
+#define N 8
+  
+// A recursive function to replace 
+// previous color 'currColor' at  '(x, y)'  
+// and all surrounding pixels of (x, y) 
+// with new color 'newColor'
+void floodFill(int myScreen[M][N], int x, int y, int currColor, int newColor) 
+{ 
+    // Base cases 
+    if (x < 0 || x >= M || y < 0 || y >= N) 
+        return; 
+    if (myScreen[x][y] != currColor) 
+        return; 
+    if (myScreen[x][y] == newColor) 
+        return; 
+  
+    // Replace the color at cell (x, y) 
+    myScreen[x][y] = newColor; 
+  
+    // Recursively call for north, east, south and west 
+    floodFill(myScreen, x+1, y, currColor, newColor); 
+    floodFill(myScreen, x-1, y, currColor, newColor); 
+    floodFill(myScreen, x, y+1, currColor, newColor); 
+    floodFill(myScreen, x, y-1, currColor, newColor); 
+} 
+  
+// It mainly finds the previous color on (x, y) and 
+// calls floodFill() 
+void findColor(int myScreen[][N], int x, int y, int newColor) 
+{ 
+    int currColor = myScreen[x][y]; 
+    floodFill(myScreen, x, y, currColor, newColor); 
+} 
+  
+// Driver program to test above function 
+int main() 
+{ 
+    int myScreen[M][N] = 
+                    {
+                      {3, 2, 1, 1, 1, 1, 1, 1}, 
+                      {1, 1, 1, 1, 1, 1, 0, 0}, 
+                      {1, 0, 0, 1, 1, 0, 1, 1}, 
+                      {1, 2, 2, 2, 2, 0, 1, 0}, 
+                      {1, 1, 1, 2, 2, 0, 1, 0}, 
+                      {1, 1, 1, 2, 2, 2, 2, 0}, 
+                      {1, 1, 1, 1, 1, 2, 1, 1}, 
+                      {1, 1, 1, 1, 1, 2, 2, 1}, 
+                     }; 
+    int x = 4, y = 4, newColor = 3; 
+    findColor(myScreen, x, y, newColor); 
+  
+    cout << "Updated myScreen : \n"; 
+    
+    //printing screen
+    for (int i=0; i<M; i++) 
+    { 
+        for (int j=0; j<N; j++) 
+           cout << myScreen[i][j] << " "; 
+        cout << endl; 
+    } 
+    return 0;
+} 
diff --git a/floodfill.cpp b/floodfill.cpp
new file mode 100644
index 0000000..57d136a
--- /dev/null
+++ b/floodfill.cpp
@@ -0,0 +1,66 @@
+#include<iostream> 
+using namespace std; 
+// Dimentions of myScreen. You may change
+#define M 8
+#define N 8
+  
+// A recursive function to replace 
+// previous color 'currColor' at  '(x, y)'  
+// and all surrounding pixels of (x, y) 
+// with new color 'newColor'
+void floodFill(int myScreen[M][N], int x, int y, int currColor, int newColor) 
+{ 
+    // Base cases 
+    if (x < 0 || x >= M || y < 0 || y >= N) 
+        return; 
+    if (myScreen[x][y] != currColor) 
+        return; 
+    if (myScreen[x][y] == newColor) 
+        return; 
+  
+    // Replace the color at cell (x, y) 
+    myScreen[x][y] = newColor; 
+  
+    // Recursively call for north, east, south and west 
+    floodFill(myScreen, x+1, y, currColor, newColor); 
+    floodFill(myScreen, x-1, y, currColor, newColor); 
+    floodFill(myScreen, x, y+1, currColor, newColor); 
+    floodFill(myScreen, x, y-1, currColor, newColor); 
+} 
+  
+// It mainly finds the previous color on (x, y) and 
+// calls floodFill() 
+void findColor(int myScreen[][N], int x, int y, int newColor) 
+{ 
+    int currColor = myScreen[x][y]; 
+    floodFill(myScreen, x, y, currColor, newColor); 
+} 
+  
+// Driver program to test above function 
+int main() 
+{ 
+    int myScreen[M][N] = 
+                    {
+                      {3, 2, 1, 1, 1, 1, 1, 1}, 
+                      {1, 1, 1, 1, 1, 1, 0, 0}, 
+                      {1, 0, 0, 1, 1, 0, 1, 1}, 
+                      {1, 2, 2, 2, 2, 0, 1, 0}, 
+                      {1, 1, 1, 2, 2, 0, 1, 0}, 
+                      {1, 1, 1, 2, 2, 2, 2, 0}, 
+                      {1, 1, 1, 1, 1, 2, 1, 1}, 
+                      {1, 1, 1, 1, 1, 2, 2, 1}, 
+                     }; 
+    int x = 4, y = 4, newColor = 3; 
+    findColor(myScreen, x, y, newColor); 
+  
+    cout << "Updated myScreen : \n"; 
+    
+    //printing screen
+    for (int i=0; i<M; i++) 
+    { 
+        for (int j=0; j<N; j++) 
+           cout << myScreen[i][j] << " "; 
+        cout << endl; 
+    } 
+    return 0;
+}