Add arg for port, show ip/dir

Author: remisarrailh

web.py

@@ -1,11 +1,35 @@
 import SimpleHTTPServer
 import SocketServer
+import sys
+import socket
+import os 
 
-PORT = 8000
 
-Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
+if len(sys.argv) > 1:
+    try:
+        PORT = int(sys.argv[1])
+    except ValueError:
+        PORT = -1
+else:
+    PORT = 8000
 
-httpd = SocketServer.TCPServer(("", PORT), Handler)
+print "WinSimpleHTTP ----v1.1--------------------"
+# Port range
+# https://stackoverflow.com/questions/113224/what-is-the-largest-tcp-ip-network-port-number-allowable-for-ipv4#113228
+if PORT < 2 or PORT > 65535:
+    print "Invalid Port : " + str(PORT)
+    print "Port must be 2-65535"
+    print "------------------------------------------"
+else:
+    path = os.path.dirname(os.path.realpath(__file__))
 
-print "serving at port", PORT
-httpd.serve_forever()
+    # How to get IP
+    # https://stackoverflow.com/questions/166506/finding-local-ip-addresses-using-pythons-stdlib
+    ip = [l for l in ([ip for ip in socket.gethostbyname_ex(socket.gethostname())[2] if not ip.startswith("127.")][:1], [[(s.connect(('8.8.8.8', 53)), s.getsockname()[0], s.close()) for s in [socket.socket(socket.AF_INET, socket.SOCK_DGRAM)]][0][1]]) if l][0][0]
+
+    
+    Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
+    httpd = SocketServer.TCPServer(("", PORT), Handler)
+    print path + " ---> " + ip + ":" + str(PORT)
+    print "------------------------------------------"
+    httpd.serve_forever()