How can I check if item is selected or visible by only having a list of Elements retrieved by sb.find_elements() ?

[Ramasj00]

Hi, see the following code snippet:

all_rows = sb.find_elements(TABLE_XPATH)
for row in rows:
    row.scroll_into_view()
    row.mouse_click()

Next thing what I want to do, is before scrolling into view and clicking the row - check if the row is selected or visible. According to the doc, the sb.is_selected(selector, by="css selector", timeout=None) expects string selector, but what I have is a list of <class 'seleniumbase.undetected.cdp_driver.element.Element'> and thus passing row as parameter would result in an exception.

Is it possible to is_selected at all in this situation? Any tips?

[mdmintz]

There's the long way if you're starting from the CDP WebElement:

SeleniumBase/seleniumbase/core/sb_cdp.py

Lines 2166 to 2190 in d4d46b7

	def is_element_visible(self, selector):
	selector = self.__convert_to_css_if_xpath(selector)
	element = None
	if ":contains(" not in selector:
	try:
	element = self.select(selector, timeout=0.01)
	except Exception:
	return False
	if not element:
	return False
	try:
	position = element.get_position()
	return (position.width != 0 or position.height != 0)
	except Exception:
	return False
	else:
	with suppress(Exception):
	tag_name = selector.split(":contains(")[0].split(" ")[-1]
	text = selector.split(":contains(")[1].split(")")[0][1:-1]
	self.loop.run_until_complete(
	self.page.select(tag_name, timeout=0.1)
	)
	self.loop.run_until_complete(self.page.find(text, timeout=0.1))
	return True
	return False

Basically, if there's 0 width and 0 height, then the element is invisible.
You can get those values from element.get_position() after you already have the element.
Much easier if you just call is_element_visible(selector) with a selector string.