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Time: 18 ms (21.34%), Space: 24 MB (16.43%) - LeetHub
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LeetCode/Medium/0049-group-anagrams/0049-group-anagrams.py

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class Solution:
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def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
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# # 1. 문자열 정렬해서 key로 사용
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# anagrams = {}
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# for word in strs:
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# return list(anagrams.values())
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# 2. 각 문자의 갯수를 key로 사용
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anagrams = {}
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for word in strs:
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counter = [0] * 26

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