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SNOW-1511473: "type[type]" is incompatible with "type[SnowflakeCursor]" #1984

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tekumara opened this issue Jun 28, 2024 · 7 comments
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bug status-triage_done Initial triage done, will be further handled by the driver team

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@tekumara
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Python version

3.9

Operating system and processor architecture

macos

Installed packages

snowflake-connector-python==3.11.0

What did you do?

*_, dcur = conn.execute_string("select 1",cursor_class=snowflake.connector.cursor.DictCursor)
dcur.fetchall()

What did you expect to see?

No type error, but get this in pyright/pylance/vscode:

CleanShot 2024-06-28 at 22 11 56@2x

Can you set logging to DEBUG and collect the logs?

No response

@github-actions github-actions bot changed the title "type[type]" is incompatible with "type[SnowflakeCursor]" SNOW-1511473: "type[type]" is incompatible with "type[SnowflakeCursor]" Jun 28, 2024
@sfc-gh-sghosh sfc-gh-sghosh self-assigned this Jul 1, 2024
@sfc-gh-sghosh
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Hello @tekumara ,

Thanks for raising the issue, we are looking into it, will update.

Regards,
Sujan

@sfc-gh-sghosh sfc-gh-sghosh added status-triage Issue is under initial triage and removed needs triage bug labels Jul 1, 2024
@sfc-gh-sghosh
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Hello @tekumara ,

Could you try the code in this way, I just tried and I am not getting any compilation error in VScode

`cursor1 = con.cursor(snowflake.connector.cursor.DictCursor)

try:
    r1 = cursor1.execute("select 1").fetchall()
finally:
    cursor1.close()`

@sfc-gh-sghosh sfc-gh-sghosh added status-triage_done Initial triage done, will be further handled by the driver team and removed status-triage Issue is under initial triage labels Jul 2, 2024
@tekumara
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tekumara commented Jul 2, 2024

That's works but I'm not using execute I'm using execute_string in my codebase to execute multiple sql statements (I simplified it for the MRE above)

@sfc-gh-sghosh
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sfc-gh-sghosh commented Jul 23, 2024

Hello @tekumara ,

You need to split the statements if using multiple statements

Example
`main_cursor = con.cursor(snowflake.connector.cursor.DictCursor)
print("cursor created")

sql_script = """
CREATE OR REPLACE TABLE my_table (id INT, name STRING);
INSERT INTO my_table VALUES (1, 'Alice'), (2, 'Bob');
SELECT * FROM my_table;
"""

# Split the script into individual statements
sql_statements = sql_script.strip().split(';')


for statement in sql_statements:
    if statement.strip():  # Only execute non-empty statements
        main_cursor.execute(statement)
        try:
            results_cursor = main_cursor.fetchall()
            for row in results_cursor:
                print(row)
        except snowflake.connector.errors.ProgrammingError:
            
            pass

main_cursor.close()
con.close()`

Output:
cursor created
{'status': 'Table MY_TABLE successfully created.'}
{'number of rows inserted': 2}
{'ID': 1, 'NAME': 'Alice'}
{'ID': 2, 'NAME': 'Bob'}

Regards,
Sujan

@tekumara
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tekumara commented Jul 23, 2024

Isn't that what execute_string does for me?

@sfc-gh-sghosh
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Hello @tekumara ,

Sorry for the dealy.
As of now, for execute_string, you have to split the statements, as recommended above.

Example:
from snowflake.connector.util_text import split_statements

def execute_file(filename, conn):
with open(filename,'r') as f:
text = f.read()
try:
for stmt in split_statements(StringIO(text)):
conn.execute_string(stmt)
except:
print("Execution aborted")

@tekumara
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Ok but I want a DictCursor and I don't really want to roll my own loop, when I could just use execute_string

ie: I want to use

conn.execute_string("select 1",cursor_class=snowflake.connector.cursor.DictCursor)

But I get this type error from pylance/vscode:

Argument of type "type[DictCursor]" cannot be assigned to parameter "cursor_class" of type "SnowflakeCursor" in function "execute_string"
  Type "type[DictCursor]" is not assignable to type "SnowflakeCursor"

Can the type annotations be fixed to prevent this error?

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