Fizz Buzz.cpp

/*
    Given number n. Print number from 1 to n. But:
        when number is divided by 3, print "fizz".
        when number is divided by 5, print "buzz".
        when number is divided by both 3 and 5, print "fizz buzz".
    
    Link: http://www.lintcode.com/en/problem/fizz-buzz/

    Example: If n = 15, you should return:
        [
          "1", "2", "fizz",
          "4", "buzz", "fizz",
          "7", "8", "fizz",
          "buzz", "11", "fizz",
          "13", "14", "fizz buzz"
        ]

    Solution: None
    
    Source: None
*/

class Solution {
public:
    /**
     * param n: As description.
     * return: A list of strings.
     */
    vector<string> fizzBuzz(int n) {
        vector<string> results;
        for (int i = 1; i <= n; i++) {
            if (i % 15 == 0) {
                results.push_back("fizz buzz");
            } else if (i % 5 == 0) {
                results.push_back("buzz");
            } else if (i % 3 == 0) {
                results.push_back("fizz");
            } else {
                results.push_back(to_string(i));
            }
        }
        return results;
    }
};