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| 1 | +//math, FFT |
| 2 | +//https://www.hackerrank.com/contests/w6/challenges/best-spot/editorial |
| 3 | +#include <stdio.h> |
| 4 | +#include <math.h> |
| 5 | +#include <algorithm> |
| 6 | +#include <vector> |
| 7 | +#include <complex> |
| 8 | +#define cpd complex<double> |
| 9 | +using namespace std; |
| 10 | +const double PI = acos(-1); |
| 11 | +int rearr[1 << 19]; |
| 12 | +int R, C,H,W; |
| 13 | +int sqx[500][500],xy[500][500]; |
| 14 | +int rev(int n, int k) { |
| 15 | + int r = 0; |
| 16 | + while (k--) { |
| 17 | + r += r + (n & 1); |
| 18 | + n >>= 1; |
| 19 | + } |
| 20 | + return r; |
| 21 | +} |
| 22 | +void FFT(vector<cpd > &A, bool inv = 0) { |
| 23 | + for (int i = 0; i < A.size(); ++i) |
| 24 | + if (rearr[i]) swap(A[i], A[rearr[i]]); |
| 25 | + int half = 1; |
| 26 | + for (int step = 2; step <= A.size(); step += step) { |
| 27 | + double theta = (PI + PI) / step; |
| 28 | + if (inv) theta = -theta; |
| 29 | + cpd w(cos(theta), sin(theta)); |
| 30 | + for (int i = 0; i < A.size(); i += step) { |
| 31 | + cpd x = 1; |
| 32 | + for (int j = 0; j < half; ++j) { |
| 33 | + cpd odd = A[i + j + half]*x; |
| 34 | + A[i + j + half] = A[i + j] - odd; |
| 35 | + A[i + j] += odd; |
| 36 | + x *= w; |
| 37 | + } |
| 38 | + } |
| 39 | + half = step; |
| 40 | + } |
| 41 | + for (int i = 0; inv && i < A.size(); ++i) A[i] /= A.size(); |
| 42 | +} |
| 43 | +int main() { |
| 44 | + int i, j,RC,p=1; |
| 45 | + int k = 0; |
| 46 | + int sqy = 0; |
| 47 | + for (scanf("%d%d", &R, &C), RC = R * C; p < RC + RC; p += p) ++k; |
| 48 | + for (i = 0; i < p; ++i) { |
| 49 | + j = rev(i, k); |
| 50 | + if (i < j) rearr[i] = j; |
| 51 | + } |
| 52 | + vector<cpd > h(p), ps(p); |
| 53 | + int ix = 0; |
| 54 | + for (i = 0; i < R; ++i,ix+=C) { |
| 55 | + for (j = 0; j < C; ++j) {//range sum |
| 56 | + scanf("%d",sqx[i]+j); |
| 57 | + h[ix + j] = h[ix + j + RC] = sqx[i][j]; |
| 58 | + sqx[i][j] *= sqx[i][j]; |
| 59 | + if (i > 0) sqx[i][j] += sqx[i - 1][j]; |
| 60 | + if (j > 0) sqx[i][j] += sqx[i][j - 1]; |
| 61 | + if (i > 0 && j > 0) sqx[i][j] -= sqx[i - 1][j - 1]; |
| 62 | + } |
| 63 | + } |
| 64 | + for (scanf("%d%d",&H,&W),i = 0,ix=RC; i < H; ++i,ix-=C) { |
| 65 | + for(j = 0; j < W; ++j) { |
| 66 | + int height; scanf("%d",&height); |
| 67 | + ps[ix - j - 1] = height; |
| 68 | + sqy += height * height; |
| 69 | + } |
| 70 | + } |
| 71 | + FFT(h); FFT(ps); |
| 72 | + for (i = 0; i < p; ++i) h[i] *= ps[i]; |
| 73 | + FFT(h, 1); |
| 74 | + for (ix = RC-1, i = 0; i < R; ++i) { |
| 75 | + for (j = 0; j <C; ++j, ++ix) { |
| 76 | + double coef = h[ix].real(); |
| 77 | + coef += coef > 0 ? 0.5 : -0.5; |
| 78 | + xy[i][j] = coef; |
| 79 | + //printf("%d\n",xy[i][j]); |
| 80 | + } |
| 81 | + } |
| 82 | + int ans = -1; |
| 83 | + int r, c; |
| 84 | + for (i = 0; i <= R-H; ++i) { |
| 85 | + for(j = 0; j <= C-W; ++j) { |
| 86 | + int sum = sqx[i+H-1][j+W-1]+sqy; |
| 87 | + if (i > 0) sum -= sqx[i - 1][j + W - 1]; |
| 88 | + if (j > 0) sum -= sqx[i + H - 1][j - 1]; |
| 89 | + if (i > 0 && j > 0) sum += sqx[i - 1][j - 1]; |
| 90 | + sum -= xy[i][j] + xy[i][j]; |
| 91 | + if (ans<0 || ans>sum) { |
| 92 | + ans = sum; |
| 93 | + r = i + 1; c = j + 1; |
| 94 | + } |
| 95 | + } |
| 96 | + } |
| 97 | + printf("%d\n%d %d",ans,r,c); |
| 98 | + |
| 99 | + return 0; |
| 100 | +} |
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