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Solution Explanation: Maximum XOR Queries

This repository contains a solution for solving the Maximum XOR Queries problem in multiple programming languages: C++, Java, JavaScript, Python, and Go. Each solution is broken down step-by-step for ease of understanding.

Problem Summary

Given an array of numbers (nums) and a parameter maximumBit, we are to find the maximum XOR result for each query by choosing an integer k that maximizes the XOR between k and the cumulative XOR of all elements in nums. The k must be within a range defined by maximumBit.

Steps to Solution

The approach is the same across all languages but adapted to the syntax of each language. Here’s a language-by-language breakdown of how each solution works.


C++ Code Explanation

  1. Initialize Variables:

    • We start by defining XORed, an integer to store the cumulative XOR of all elements in nums.
    • We also define max_k, which is the maximum value achievable with maximumBit bits. This is calculated as 2^maximumBit - 1.
  2. Compute Initial XOR:

    • Using a loop, XOR all elements in nums together to get an initial cumulative XOR (XORed) of the entire array.
  3. Process Each Query in Reverse:

    • We loop from the last element of nums to the first.
    • For each query, calculate k as XORed ^ max_k. This gives the integer k that maximizes the XOR.
    • Append k to our answer array.
    • Update XORed by removing the effect of the last element in nums.
  4. Return the Result:

    • The final answer array contains the results for all queries, and we return it.

Java Code Explanation

  1. Initialize Variables:

    • Define XORed to store the cumulative XOR of all elements in nums.
    • Calculate max_k as (1 << maximumBit) - 1 to get the maximum value achievable within maximumBit bits.
  2. Compute Initial XOR:

    • Use a loop to XOR all elements in nums, updating XORed with each element.
  3. Reverse Loop for Queries:

    • Loop backward from the last element of nums.
    • For each query, calculate k as XORed ^ max_k.
    • Store k in the answer array.
    • Update XORed by XORing it with the current element to "remove" its effect.
  4. Return the Final Answer:

    • The answer array now contains all query results, which we return as our solution.

JavaScript Code Explanation

  1. Initialize Variables:

    • Define XORed to store the cumulative XOR of all numbers in nums.
    • Calculate max_k as (1 << maximumBit) - 1 to get the highest possible value within maximumBit bits.
  2. Compute Initial XOR:

    • Loop over nums and calculate the cumulative XOR (XORed).
  3. Process Each Query in Reverse:

    • Start from the last element of nums and work backwards.
    • For each query, calculate k as XORed ^ max_k.
    • Store k in the answer array.
    • Update XORed by removing the effect of the last element.
  4. Return the Final Array:

    • Return answer as the array containing all query results.

Python Code Explanation

  1. Initialize Variables:

    • Define XORed to hold the cumulative XOR of all elements in nums.
    • Calculate max_k as (1 << maximumBit) - 1 to get the largest value allowed by maximumBit.
  2. Compute Cumulative XOR:

    • Loop through each number in nums to calculate the cumulative XOR.
  3. Process Each Query in Reverse:

    • Start from the last element of nums and process each in reverse.
    • For each query, calculate k as XORed ^ max_k to get the maximum XOR.
    • Append k to the answer list.
    • Update XORed by XORing it with the last element in nums.
  4. Return Results:

    • answer now holds the maximum XOR result for each query, which we return as the solution.

Go Code Explanation

  1. Initialize Variables:

    • Define XORed to keep the cumulative XOR of all elements in nums.
    • Calculate max_k as (1 << maximumBit) - 1 to get the maximum possible integer with maximumBit bits.
  2. Compute Initial XOR:

    • XOR all elements in nums to get the cumulative XOR.
  3. Process Each Query in Reverse:

    • Start from the end of nums and move backwards.
    • For each query, calculate k as XORed ^ max_k.
    • Add k to the answer slice.
    • Update XORed by removing the effect of the last element.
  4. Return the Result Slice:

    • Return answer as the final result, containing the XOR values for each query.