13罗马数字转整数.py

class Solution:
    def romanToInt(self, s: str) -> int:
        # value = {'IV':4,'IX':9,'XL':40,'XC':90,'CD':400,'CM':900} 
        value1 = {'I':1,'V':5,'X':10,'L':50,'C':100,'D':500,'M':1000}
        z = 0
        # for i,j in value.items():
        #     if s:
        #         if i in s:
        #             z += s.count(i)*j
        #             s=s.replace(i,'')
        #     else:
        #         return z
        # for i1,j1 in value1.items():
        #     if s:
        #         if i1 in s:
        #             z += s.count(i1)*j1
        #             s=s.replace(i1,'')
        #     else:
        #         return z
        for i in range(len(s)):            
            if i<len(s)-1 and value1[s[i]]<value1[s[i+1]]:                
                z-=value1[s[i]]
            else:
                z+=value1[s[i]]
        return z
print(Solution().romanToInt('IX'))