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Copy pathMergeSort - CountSplitInv.py
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MergeSort - CountSplitInv.py
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################################################################################
## Copyright(c) Arsalan Khairani, 2014 ##
## Merge Sort ##
## ##
## Divide and Conquer merge sort algorithm. Integer to store inversions. ##
## File Input: Unordered Integer 1 to 10000 ##
################################################################################
def MergeSort(left, right, arr):
# Base case
if left == right:
a = []
a.append(arr[left])
return [a, 0]
# Call of left half
half = int((left + right)/2)
leftTreeAndInversions = MergeSort (left, half, arr)
# Call on right half
rightTreeAndInversions = MergeSort (half + 1, right, arr)
# Call Merge
sortAndSplitInv = Merge_CountSplitInv(leftTreeAndInversions[0], rightTreeAndInversions[0])
# Add inversions
sortAndSplitInv[1] += leftTreeAndInversions[1] + rightTreeAndInversions[1]
return sortAndSplitInv
def Merge_CountSplitInv(leftTree, rightTree):
i = 0
j = 0
arr = []
splitInversions = 0
for k in range(len(leftTree)+len(rightTree)):
# In case of any one array is fully copied
if i == len(leftTree):
arr.append(rightTree[j])
j += 1
elif j == len(rightTree):
arr.append(leftTree[i])
i+= 1
# In case both have elements then copy the greatest
elif leftTree[i] > rightTree[j]:
arr.append(rightTree[j])
# Counting split inversion
splitInversions += (len(leftTree) - i)
j+= 1
else:
arr.append(leftTree[i])
i+= 1
return [arr, splitInversions]
file = open("IntegerArray.txt")
Array = []
for line in file:
Array.append(int(line.strip('\n')))
s = MergeSort (0, 99999, Array)
print (s[1])