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UofT-DSI | sql - Assignment 1 #1

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Nov 6, 2025
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6 changes: 5 additions & 1 deletion 02_activities/assignments/DC_Cohort/Assignment1.md
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Expand Up @@ -205,5 +205,9 @@ Consider, for example, concepts of fariness, inequality, social structures, marg


```
Your thoughts...
Databases are not simply neutral tools that we use in daily life, but they are also social artifacts that carry built-in values. They reflect choices about what to track, what options to offer and what counts as a "valid” entry. Those choices shape who is visible to the system and who is left out.
For example, in databases with Race as a field with fixed categories, people with mixed background or communities not listed may feel erased or forced into inaccurate boxes. When databases are designed with rigidity, the downsides often fall on minority groups with less power, less visibility and lower socioeconomic status. In addition, the presence of “missing values” is not only technical gaps, but they often reflect on unchecked marginalization.
It is also important to consider whether it is truly necessary to collect certain information, especially sensitive information such as race, religion, disability, immigration status and more. Even seemingly “neutral” fields such as postal codes, could act as a proxy for socio-economic status. For databases used in the vulnerable sectors, it is especially important to for designers to explain why data is collected and ensure encryption and give people choices to review and update their records with ease.
Because society now relies on large databases for daily operations such as banking, human resources, applying for benefits and more, poor design can put people in difficult situations. A good database should be designed with care and ethical considerations, so that the databases can serve everyone, not just those who fit into the boxes.

```
72 changes: 55 additions & 17 deletions 02_activities/assignments/DC_Cohort/assignment1.sql
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Expand Up @@ -4,17 +4,22 @@

--SELECT
/* 1. Write a query that returns everything in the customer table. */


SELECT *
FROM customer;

/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */


SELECT *
From customer
ORDER BY customer_last_name, customer_first_name
LIMIT 10;

--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */

SELECT *
FROM customer_purchases
WHERE product_id = 4
OR product_id = 9;


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -23,47 +28,72 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
2. one condition using BETWEEN
*/
-- option 1

SELECT *, quantity*cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE customer_id >= 8
AND customer_id <=10 ;

-- option 2


SELECT *, quantity*cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE customer_id BETWEEN 8 AND 10 ;

--CASE
/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz.
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */


SELECT product_id, product_name
,CASE WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END as prod_qty_type_condensed
FROM product;

/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */


SELECT product_id, product_name
,CASE WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END as prod_qty_type_condensed
,CASE WHEN product_name LIKE '%pepper%' THEN '1'
ELSE '0'
END as pepper_flag
FROM product;

--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */



SELECT *
FROM vendor
INNER JOIN vendor_booth_assignments
ON vendor_booth_assignments.vendor_id = vendor.vendor_id
ORDER BY vendor_name, market_date;

/* SECTION 3 */

-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */
SELECT vendor_id,
COUNT (vendor_id)


FROM vendor_booth_assignments
GROUP by vendor_id ;

/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

SELECT *,
SUM (customer_purchases.quantity * customer_purchases.cost_to_customer_per_qty) AS total_spent
FROM customer_purchases
INNER JOIN customer
ON customer_purchases.customer_id = customer.customer_id
GROUP by customer.customer_id, customer.customer_first_name,customer.customer_last_name
HAVING total_spent > 2000
ORDER BY customer_last_name, customer_first_name;


--Temp Table
Expand All @@ -77,8 +107,16 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/
--create the table from the original_
DROP TABLE IF EXISTS temp.new_vendor;

CREATE TABLE temp.new_vendor AS

SELECT *
FROM vendor ;
--insert the new 10th vendor
INSERT INTO temp.new_vendor (vendor_id, vendor_name,vendor_type,vendor_owner_first_name, vendor_owner_last_name)
VALUES (10, 'Thomass Superfood Store', 'a Fresh Focused store', 'Thomas', 'Rosenthal');

-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
Expand Down
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