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India - Water #21

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39 changes: 33 additions & 6 deletions lib/exercises.rb
Original file line number Diff line number Diff line change
@@ -1,19 +1,46 @@

# This method will return an array of arrays.
# Each subarray will have strings which are anagrams of each other
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(n)

def grouped_anagrams(strings)
Comment on lines +4 to 7

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👍 Since you're sorting the strings, the time complexity is O(n + m log m) where m is the length of the words, but if you assume the strings are limited in size, you can say it's O(n).

raise NotImplementedError, "Method hasn't been implemented yet!"
anagrams = {}
strings.each do |string|
sorted_string = string.split('').sort.join
if anagrams[sorted_string]
anagrams[sorted_string] << string
else
anagrams[sorted_string] = [string]
end
end
return anagrams.values
end

# This method will return the k most common elements
# in the case of a tie it will select the first occuring element.
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(nlog(n))
# Space Complexity: O(n)
def top_k_frequent_elements(list, k)
Comment on lines +22 to 24

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👍

raise NotImplementedError, "Method hasn't been implemented yet!"
return list if list.length == k
return [] if list.length == 0
frequency = {}
list.each do |element|
if frequency[element]
frequency[element] += 1
else
frequency[element] = 1
end
end

sorted_hash = frequency.sort_by{|k, v| -v}
result = []
index = 0
k.times do
result << sorted_hash[index][0]
index += 1
end
return result
end


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