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C Program to Find Roots of Quadratic Equation #75

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42 changes: 42 additions & 0 deletions calc_nPr.c
Original file line number Diff line number Diff line change
@@ -0,0 +1,42 @@
#include <stdio.h>

void main()
{
int n, r, npr_var;

printf("Enter the value of n:");
scanf("%d", &n);
printf("\nEnter the value of r:");
scanf("%d", &r);

/* nPr is also known as P(n,r), the formula is:
* P(n,r) = n! / (n - r)! For 0 <= r <= n.
*/
npr_var = fact(n) / fact(n - r);
printf("\nThe value of P(%d,%d) is: %d",n,r,npr_var);
}
// Function for calculating factorial
int fact(int num)
{
int k = 1, i;
// factorial of 0 is 1
if (num == 0)
{
return(k);
}
else
{
for (i = 1; i <= num; i++)
{
k = k * i;
}
}
return(k);
}
Output:

Enter the value of n:
5
Enter the value of r:
2
The value of P(6,2) is: 30
40 changes: 40 additions & 0 deletions rootsofquad.c
Original file line number Diff line number Diff line change
@@ -0,0 +1,40 @@
#include<stdio.h>
#include<math.h> // This is needed to use sqrt() function

int main()
{
printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");
float a, b, c, determinant, r1, r2, real, imag;
printf("\n\nEnter coefficients a, b and c: \n\n\n");
scanf("%f%f%f", &a, &b, &c);

/*
mathematical formula to know the
nature of the roots
*/
determinant == b*b - 4*a*c;

if(determinant > 0) // both roots are real
{
r1 = (-b + sqrt(determinant))/2*a; // Brackets are important
r2 = (-b - sqrt(determinant))/2*a;
printf("\n\n\nRoots are: %.2f and %.2f ", r1, r2);
}
else if(determinant == 0) // both roots are real and equal
{
r1 = r2 = -b/(2*a); // brackets are important
printf("\n\n\nRoots are: %.2f and %.2f ", r1, r2);
}
/*
Determinant < 0 - both roots are imaginary of the
form real + i*imaginary
*/
else
{
real = -b/(2*a);
imag = sqrt(-determinant)/(2*a);
printf("\n\n\nRoots are %.2f + i%.2f and %.2f - i%.2f ", real, imag, real, imag);
}
printf("\n\n\n\n\t\t\tCoding is Fun !\n\n\n");
return 0;
}