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Use non-strict comparison in FilterByReferenceOperation (#37)
It is comparing Node instances, and those are not the same… that leads to the comparison failing, even though they are semantically equal. The "proper" way would be to check by some custom method (e.g. an `equals()` method on `Node`), but going back to non-strict comparison here is fine. Note: Not just removing the `true` on `is_array()` to clarify the intention. Taken from #36 and amended.
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