Added zero, iszero, one, isone to dual #74
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Cool, thanks for the contribution. Could you add tests? |
src/dual.jl
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| Base.zero(::Type{Dual{T}}) where {T} = Dual(zero(T), zero(T)) | ||
| Base.zero(x::Dual{T}) where {T} = zero(T) | ||
| Base.iszero(z::Dual{T}) where {T} = iszero(value(z)) & iszero(epsilon(z)) |
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Is there a reason not to use short-circuiting && here and for isone?
src/dual.jl
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| Base.zero(::Type{Dual{T}}) where {T} = Dual(zero(T), zero(T)) | ||
| Base.zero(x::Dual{T}) where {T} = zero(T) | ||
| Base.iszero(z::Dual{T}) where {T} = iszero(value(z)) & iszero(epsilon(z)) |
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This definition of iszero is inconsistent with how == 0 is defined for duals:
Line 167 in 52a6061
src/dual.jl
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| Base.round(::Type{T}, z::Dual) where {T<:Real} = round(T, value(z)) | ||
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| Base.zero(::Type{Dual{T}}) where {T} = Dual(zero(T), zero(T)) | ||
| Base.zero(x::Dual{T}) where {T} = zero(T) |
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Why should these two versions of zero return different types?
| Base.round(::Type{T}, z::Dual) where {T<:Real} = round(T, value(z)) | ||
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| Base.zero(::Type{Dual{T}}) where {T} = Dual(zero(T), zero(T)) | ||
| Base.zero(x::Dual{T}) where {T} = zero(typeof(x)) |
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Why not
| Base.zero(x::Dual{T}) where {T} = zero(typeof(x)) | |
| Base.zero(::Dual{T}) where {T} = zero(Dual{T}) |
| using LinearAlgebra | ||
| import DualNumbers: value | ||
| import NaNMath | ||
| import Base: one, isone, zero, iszero |
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These are exported from base, so this is unnecessary.
| import Base: one, isone, zero, iszero |
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You need to explicitly import it to extend it. Try this.
struct ABC end
one(x::ABC) = 1
Will give you the error
ERROR: error in method definition: function Base.one must be explicitly imported to be extended
Stacktrace:
[1] top-level scope at none:0
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I know that, but they are not being extended in the tests.
Co-Authored-By: Benoit Pasquier <[email protected]>
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