give way more score for killing a flag thief #1302
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You need to test locally (self-review) before requesting a review |
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Okay... I thought the change is trivial |
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Self review done |
| @@ -191,7 +191,7 @@ local function calculate_killscore(player) | |||
| local flag_multiplier = 1 | |||
| for tname, carrier in pairs(ctf_modebase.flag_taken) do | |||
| if carrier.p == player then | |||
| flag_multiplier = flag_multiplier + 0.25 | |||
| flag_multiplier = flag_multiplier * 2 | |||
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I'm pretty sure this is a literal exponential increase. For now I'd suggest this instead:
| flag_multiplier = flag_multiplier * 2 | |
| flag_multiplier = flag_multiplier + 1 |
That should result in the score being the normal(?) kill score * the number of flags they have, starting at x2 for one flag
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Yes it's an exponential increase. Getting flag of one team is not that hard. But getting flag of one team and at the same time getting flag of another one, is extremely hard. You have teammembers of the first team on your tail, everyone know your location every second, and then you have to approach base of another team to get their flag.
Therefore, I think exponential makes perfect sense.
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The suggestion is trying to encourage people to kill flag carriers, what you're saying is maybe justification for rewarding the flag carrier.
If this score increase isn't enough it could be changed to +2 or more, but I think a linear increase keeps the focus on killing "someone with a flag"
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Maybe put it to a vote among players?
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Or otherwise ask for a third party opinion. Since I don't agree with you, a third party opinion helps.
The suggestion originates from here: https://discord.com/channels/447819017391046687/448136308108296213/1246872747838279710
The flag multiplier which multiplies the score is 1 for no flag, and multiplied by 2 for each flag added. Like 2 for a flag and 4 for two flags. Because it's way harder to not get killed and steal the second flag.