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feat : 유저등급별 페이지 및 관리자 페이지 API 설계(SJB-step2) #3

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@sjb7773 sjb7773 commented May 19, 2023

Filter를 사용한 로그인 회원 체크 로직 리팩터링
RoleMypageController와 MEMER_ROLE enum domain을 통한 유저 등급별 접근 페이지 설계
Filter를 사용한 관리자 페이지 설정 및 관리자 페이지에서 유저 등급 권한 조작 가능
IntelliJ Actions On Save기능을 사용한 코드 스타일 정리

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살짝만 더 수정해보세요~



public List<Member> findMembers() {
return memberRepository.findAll();
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어떤 추가적인 Validation 작업이 필요할 수도 있지 않을까요?
(데이터가 없다거나, 조회가 불가능한 권한이 있다거나...)

import java.util.List;
import java.util.Optional;

public interface MemberRepository {
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개발하는 입장에서, 사실 메모리/JPA를 나눌 필요가 있나 싶어요.
이후 다른 스텝 할 때도 두개 다 하기 힘드니까, 그냥 하나만 하세요 ㅋㅋㅋ

return Arrays.stream(request.getCookies())
.filter(cookie -> cookie.getName().equals(cookieName))
.findAny()
.orElse(null);
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어디에서는 Optional을 쓰고, 어디에서는 null을 쓰는데, 사실 하나로 로직을 통합하는게 나을 것 같아요.


//if-else문의 문제점 존재 -> 더 나은 방식 없을까?
public String RoleDistributor(MEMBER_ROLE member_role) {
if (member_role == MEMBER_ROLE.ROLE_ADMIN) {
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Switch 방식으로 변경하시거나, enum안에 property를 넣고 그 값을 반환하는 방식으로 처리해 주세요.

public String acceptRoleChange(@RequestParam("memberId") String memberId,
@RequestParam("member_role") MEMBER_ROLE member_role) {
System.out.println("memberId = " + memberId);
System.out.println("member_role = " + member_role);
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System.out.println 은 좋지 않아요.
로거로 바꿔주세요.

@sjb7773
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sjb7773 commented May 30, 2023

넵 확인했습니다! 감사합니다 ㅎㅎ

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