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Create merge-bsts-to-create-single-bst.py
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kamyu104 authored Jul 13, 2021
1 parent 2140b34 commit 887cfb0
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69 changes: 69 additions & 0 deletions Python/merge-bsts-to-create-single-bst.py
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# Time: O(n)
# Space: O(n)

# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, val=0, left=None, right=None):
pass


class Solution(object):
def canMerge(self, trees):
"""
:type trees: List[TreeNode]
:rtype: TreeNode
"""
def find_leaves_and_roots(trees, leaf_vals_set, val_to_root):
for root in trees:
val_to_root[root.val] = root
q = [root]
while q:
new_q = []
for node in q:
if node.left is None and node.right is None:
if node is not root:
leaf_vals_set.add(node.val)
continue
if node.left:
new_q.append(node.left)
if node.right:
new_q.append(node.right)
q = new_q

def find_root(trees, left_vals_set, val_to_root):
root = None
for node in trees:
if node.val in leaf_vals_set:
continue
if root: # multiple roots
return None
root = node
return root

def merge_bsts(root, left_vals_set, val_to_root):
if not root:
return None
del val_to_root[root.val]
q = [(root, float("-inf"), float("inf"))]
while q:
new_q = []
for node, left, right in q:
if not (left < node.val < right):
return None
if node.left:
if node.left.val in leaf_vals_set and node.left.val in val_to_root:
node.left = val_to_root[node.left.val]
del val_to_root[node.left.val]
new_q.append((node.left, left, node.val))
if node.right:
if node.right.val in leaf_vals_set and node.right.val in val_to_root:
node.right = val_to_root[node.right.val]
del val_to_root[node.right.val]
new_q.append((node.right, node.val, right))
q = new_q
return root if not val_to_root else None

leaf_vals_set, val_to_root = set(), {}
find_leaves_and_roots(trees, leaf_vals_set, val_to_root)
root = find_root(trees, leaf_vals_set, val_to_root)
return merge_bsts(root, leaf_vals_set, val_to_root)

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