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Added codes for 31 March
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Tanmay-312 committed Mar 31, 2024
1 parent a19a286 commit 24434f2
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135 changes: 135 additions & 0 deletions GeeksForGeeks/March/31-3-24/GFG.java
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//{ Driver Code Starts
// Initial Template for Java

import java.io.*;
import java.util.*;
import java.util.LinkedList;
import java.util.Queue;

class Node {
int key;
Node left;
Node right;

Node(int x) {
this.key = x;
left = null;
right = null;
}
}

class GfG {

static Node buildTree(String str) {

if (str.length() == 0 || str.charAt(0) == 'N') {
return null;
}

String ip[] = str.split(" ");
// Create the root of the tree
Node root = new Node(Integer.parseInt(ip[0]));
// Push the root to the queue

Queue<Node> queue = new LinkedList<>();

queue.add(root);
// Starting from the second element

int i = 1;
while (queue.size() > 0 && i < ip.length) {

// Get and remove the front of the queue
Node currNode = queue.peek();
queue.remove();

// Get the current node's value from the string
String currVal = ip[i];

// If the left child is not null
if (!currVal.equals("N")) {

// Create the left child for the current node
currNode.left = new Node(Integer.parseInt(currVal));
// Push it to the queue
queue.add(currNode.left);
}

// For the right child
i++;
if (i >= ip.length) break;

currVal = ip[i];

// If the right child is not null
if (!currVal.equals("N")) {

// Create the right child for the current node
currNode.right = new Node(Integer.parseInt(currVal));

// Push it to the queue
queue.add(currNode.right);
}
i++;
}

return root;
}

public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

int t = Integer.parseInt(br.readLine());

while (t > 0) {
String s = br.readLine();
int N = Integer.parseInt(br.readLine());
Node root = buildTree(s);
Solution g = new Solution();
System.out.println(g.findMaxForN(root, N));
t--;
}
}
}

// } Driver Code Ends


// User function Template for Java

/*class Node
{
int key;
Node left, right;
Node(int x)
{
key = x;
left = right = null;
}
}*/
class Solution
{
static int max=-1;

public static int findMaxForN(Node root, int n)
{
traverse(root,n);
int ans = max;
max = -1;
return ans;
}

public static void traverse(Node root,int n)
{
if(root==null)
return;

traverse(root.left,n);
if(root.key>max&&root.key<=n)
max = root.key;

traverse(root.right,n);
}
}
2 changes: 2 additions & 0 deletions GeeksForGeeks/March/31-3-24/README.md
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Time complexity - O(n)
Space complexity - O(n)
2 changes: 2 additions & 0 deletions LeetCode/March/31-3-24/README.md
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Time complexity - O(n)
Space complexity - O(1)
23 changes: 23 additions & 0 deletions LeetCode/March/31-3-24/Solution.java
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class Solution
{
public long countSubarrays(int[] nums, int minK, int maxK)
{
long ans = 0;
int j = -1;
int prevMinKIndex = -1;
int prevMaxKIndex = -1;

for (int i = 0; i < nums.length; ++i)
{
if (nums[i] < minK || nums[i] > maxK)
j = i;
if (nums[i] == minK)
prevMinKIndex = i;
if (nums[i] == maxK)
prevMaxKIndex = i;
ans += Math.max(0, Math.min(prevMinKIndex, prevMaxKIndex) - j);
}

return ans;
}
}

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